如何在mongodb查询中传递一个空的php变量

Question

我想创建一个动态mongodb查询,如果条件为真,则插入其聚合的每个部分,否则不注入该部分.

例如,我想检查时间是否在凌晨1点到8点之间.如果是,则将定义的数组传递给mongodb查询,否则不传递任何内容.

if ($this->Not_in_1_8 == true) {
    $this->N_IN_1_8 = array('dont_show_between_1_n_8' => array('$ne' => true));
}else {
    $this->N_IN_1_8 = null;
}
$MidnightCheck = $this->N_IN_1_8;
$this->campaign = Bcamp::raw(function ($collection) use ($seat_category_list, $banner_size, $seat_filter_list, $gold_network, $MidnightCheck) {
    return $collection->aggregate([
        [
            '$match' => [
                '$and' => [
                    ["targets.cats" => [
                        '$in' => $seat_category_list
                        ]
                    ],
                    ['banners.' . $banner_size => [
                        '$exists' => true
                        ]
                    ],
                    ['href' => [
                        '$nin' => $seat_filter_list
                        ]
                    ],
                    ['targets.gold_network' => [
                        '$eq' => $gold_network
                        ]
                    ],
                    ['status' => [
                        '$ne' => "Low_Budget"
                        ]
                    ],
                    ['daily_budget_status' => [
                        '$ne' => "Low_Budget"
                        ]
                    ],
                    $MidnightCheck
                ]
            ]
        ],
        [
            '$project' => [
                'ab' => [
                    '$cmp' => [
                        '$budget', '$click_cost'
                    ]
                ]
            ]
        ],
        [
            '$match' => [
                'ab' => [
                    '$lt' => 1
                ]
            ]
        ]

    ]);
});

但是在这个例子中它将在查询中注入null并使其成错,并且我捕获错误: bad query: BadValue: $or/$and/$nor entries need to be full objects

我改变它$this->N_IN_1_8 = '';仍然没有成功.

我需要一个中性变量或条件来传入,如果条件为false,则不会影响查询.任何的想法？

仅供参考:我正在使用带有jenssegers/laravel-mongodb包的Laravel 5.3框架来处理mongodb

Answer 1

更愿意保持代码结构不变，即当条件代码中未使用预构建数组时，您可以保留$MidnightCheckasnull并将数组包装为array_filter：

return $collection->aggregate([
[
    '$match' => [
        '$and' => array_filter([
            ["targets.cats" => ['$in' => $seat_category_list]],
            ['banners.' . $banner_size => ['$exists' => true]],
            ['href' => ['$nin' => $seat_filter_list]],
            ['targets.gold_network' => ['$eq' => $gold_network]],
            ['status' => ['$ne' => "Low_Budget"]],
            ['daily_budget_status' => ['$ne' => "Low_Budget"]],
            $MidnightCheck
        ])
    ]
// ...

不带第二个参数的调用array_filter将从数组中过滤掉所有错误值，从而导致不需要的值$MidnightCheck消失。

我认为可能更清楚的是在回调中预先准备条件：

$conditions = [
    ["targets.cats" => ['$in' => $seat_category_list]],
    ['banners.' . $banner_size => ['$exists' => true]],
    ['href' => ['$nin' => $seat_filter_list]],
    ['targets.gold_network' => ['$eq' => $gold_network]],
    ['status' => ['$ne' => "Low_Budget"]],
    ['daily_budget_status' => ['$ne' => "Low_Budget"]],
];
if ($MidnighCheck) {
    $conditions[] = $MidnightCheck;
}
return $collection->aggregate([
    ['$match' => [ '$and' => $conditions ],]
])