不需要的NHibernate更新命令

Question

我有以下课程

public class Contact
{
    public Contact() {
        Addresses = new List<Address>();
        EmailAddresses = new List<EmailAddress>();
        PhoneNumbers = new List<PhoneNumber>();
    }
    public virtual int ContactID { get; private set; }
    public virtual Firm Firm { get; set; }
    public virtual ContactType ContactType { get; set; }
    public virtual string FullName { get; set; }
    public virtual string FiscalCode { get; set; }
    public virtual string Notes { get; set; }
    public virtual ContactRole ContactRole { get; set; }

    public virtual IList<Address> Addresses { get; private set; }
    public virtual IList<EmailAddress> EmailAddresses { get; private set; }
    public virtual IList<PhoneNumber> PhoneNumbers { get; private set; }
}

public class Address
{
    public virtual int AddressID { get; private set; }
    public virtual string StreetAddress { get; set; }
    public virtual string ZipCode { get; set; }
    public virtual string City { get; set; }
    public virtual Province Province { get; set; }
    public virtual Country Country { get; set; }
    public virtual Contact Contact { get; set; }
    public virtual AddressType AddressType { get; set; }
    public virtual bool PostalAddress { get; set; }
}

这些类已使用FluentNHibernate映射到数据库.这些是映射类

public ContactMap() {
    Table( "Contacts" );
    Id( c => c.ContactID ).Column( "ContactID" ).GeneratedBy.Identity();
    References( c => c.Firm ).Column( "FirmID" );
    References( c => c.ContactType ).Column( "ContactTypeID" );
    Map( c => c.FullName );
    Map( c => c.FiscalCode );
    Map( c => c.Notes );
    References( c => c.ContactRole ).Column( "ContactRoleID" );
    HasMany( c => c.Addresses ).Cascade.SaveUpdate();
    HasMany( c => c.EmailAddresses ).Cascade.SaveUpdate();
    HasMany( c => c.PhoneNumbers ).Cascade.SaveUpdate();
}


public AddressMap() {
    Table( "Addresses" );
    Id( a => a.AddressID ).Column( "AddressID" ).GeneratedBy.Identity();
    Map( a => a.StreetAddress );
    Map( a => a.ZipCode );
    Map( a => a.City );
    References( a => a.Province ).Column( "ProvinceID" );
    References( a => a.Country ).Column( "CountryID" );
    References( a => a.Contact ).Column( "ContactID" );
    References( a => a.AddressType ).Column( "AddressTypeID" );
    Map( a => a.PostalAddress );
}

我试图使用这些类在数据库中加载大量的联系人.创建这些对象的代码可以在逻辑上解释如下

Create a contact
For each address of this contact 
    create an address
    set the contact address
    add the address to the contact collection
Next
For each email of this contact 
    create an email
    set the contact email
    add the email to the contact collection
Next

我对所有后代集合没有问题,比如Email,PhoneNumber,除了我的地址有问题.事实上,当我尝试插入至少有一个地址的联系人时,我收到以下错误

Could not insert collection: [GSLConverter.Entities.Contact.Addresses#3551][SQL: UPDATE Addresses SET AuthorID = @p0 WHERE AddressID = @p1]
Invalid column name 'AuthorID'

而不是使用ContactID使用AuthorID.AuthorID来自哪里????

这些是NHibernate在服务器上执行的查询

INSERT INTO Addresses (StreetAddress, ZipCode, City, PostalAddress, ProvinceID, CountryID, ContactID, AddressTypeID) VALUES (@p0, @p1, @p2, @p3, @p4, @p5, @p6, @p7); 
select SCOPE_IDENTITY();
@p0 = 'xxx xxxxxx, 69 ', @p1 = '80142', @p2 = 'xxxxxx', @p3 = False, @p4 = 1, @p5 = 113, @p6 = 3632, @p7 = 1

UPDATE Addresses SET AuthorID = @p0 WHERE AddressID = @p1;
@p0 = 3632, @p1 = 26

@Stefan Steinegger:这是引用AuthorID成员的类的唯一映射

public IssueNoteMap() {
    Table( "IssueNotes" );
    Id( ino => ino.IssueNoteID ).Column( "IssueNoteID" ).GeneratedBy.Identity();
    References( ino => ino.Issue ).Column( "IssueID" );
    Map( ino => ino.NoteDate );
    Map( ino => ino.NoteTitle );
    Map( ino => ino.NoteBody );
    References( ino => ino.Author ).Column( "AuthorID" );
}

AuthorID字段是对Contact表的引用,尚未映射到Contact端(如前面的Contact映射所示)

Answer 1

是IssueNote.Author一种类型的任何机会Contact？如果是这样Fluent Mapping的话

References( ino => ino.Author ).Column( "AuthorID" );

正试图更新你的'地址'表,以确保它也ContactId存储在AuthorId你告诉它的外键中IssueNote.Author映射到Contacts 时使用

你告诉nHibernate这个:

当你真的想要这个:

因此,将IssueNoteMap更改为以下内容,以便ContactId用于映射作者,它应该可以工作

References( ino => ino.Author ).Column( "ContactId" );