打印出从列表的Y元素中选择的X个不同对象的所有组合

Question

例如,52张牌的扑克牌中的5张牌= 2598960种组合.
我怎么会实际显示所有这些组合？

查找号码的代码很简单:

def binomial_coef(total,subset)
  factorial(total) / (factorial(subset) * factorial(total - subset))
end

def factorial(n)
  n.downto(1).inject(:*)
end

# different 5 card poker hand combinations
cards = 52
hand_number = 5

puts binomial_coef(cards, hand_number)

有关打印出所有实际组合的解决方案的任何想法？
例如:

1,2,3,4,5
1,2,3,4,6
等

甚至帮助开始.谢谢!

Answer 1

你需要 Array#combination

cards = (1..52).to_a
hand_number = 5
cards.combination(hand_number).to_a

=> [[1,2,3,4,5],[1,2,3,4,6],...]