我打开巨大的(11Gb)文件,将其映射到内存,但无法搜索文件中的字符串
我的代码是
if ( (fd = open("l", O_RDONLY)) < 0 ) err_sys("Cant open file");
if ( fstat(fd, &statbuf) < 0 ) err_sys("Cant get file size");
printf("size is %ld\n", statbuf.st_size);
if ( (src = mmap(0, statbuf.st_size, PROT_READ, MAP_SHARED, fd, 0)) == MAP_FAILED ) err_sys("Cant mmap");
printf("src pointer is at %ld\n", src);
char * index = strstr(src, "bin/bash");
printf("needle is at %ld\n", index);
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它适用于小文件,但在巨大的源上返回 0。我应该使用什么函数来搜索巨大的映射文件?
输出是:
size is 11111745740
src pointer is at 140357526544384
needle is at 0
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您不应该使用strstr()在内存映射文件中搜索文本:
strstr则将继续扫描文件末尾以外的位置,通过尝试读取未映射的内存来调用未定义的行为。您可以改为使用具有等效语义但应用于原始内存的函数,而不是memmem()在 Linux 和 BSD 系统上可用的 C 字符串:
void *memmem(const void *p1, size_t size1, const void *p2, size_t size2);
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请注意,您还使用了错误的printf格式:它应该是%pandsrc并且index您可能更喜欢将偏移量打印为 aptrdiff_t或 an unsigned long long:
if ((fd = open("l", O_RDONLY)) < 0)
err_sys("Cannot open file");
if (fstat(fd, &statbuf) < 0)
err_sys("Cannot get file size");
printf("size is %llu\n", (unsigned long long)statbuf.st_size);
if ((src = mmap(0, statbuf.st_size, PROT_READ, MAP_SHARED, fd, 0)) == MAP_FAILED)
err_sys("Cannot mmap");
printf("src pointer is at %p\n", (void*)src);
char *index = memmem(src, statbuf.st_size, "bin/bash", strlen("bin/bash"));
printf("needle is at %p\n", (void*)index);
if (index != NULL)
printf("needle is at offset %llu\n", (unsigned long long)(index - src));
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如果memmem在您的平台上不可用,这里有一个简单的实现:
#include <string.h>
void *memmem(const void *haystack, size_t n1, const void *needle, size_t n2) {
const unsigned char *p1 = haystack;
const unsigned char *p2 = needle;
if (n2 == 0)
return (void*)p1;
if (n2 > n1)
return NULL;
const unsigned char *p3 = p1 + n1 - n2 + 1;
for (const unsigned char *p = p1; (p = memchr(p, *p2, p3 - p)) != NULL; p++) {
if (!memcmp(p, p2, n2))
return (void*)p;
}
return NULL;
}
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