C - 按迭代位置将两个数组合二为一

Question

我在将两个数组合二为一时遇到问题，但我需要一个一个地放置一个元素，所以我有以下几点：

arr1[0] = 1; arr2[0] = 12;
arr1[1] = 2; arr2[1] = 20;
arr1[2] = 3; arr2[2] = 30;
arr1[3] = 4; arr2[3] = 40;
arr1[4] = 5; arr2[4] = 50;
arr1[5] = 6; arr2[5] = 60;
arr1[6] = 7; arr2[6] = 70;
arr1[7] = 8; arr2[7] = 80;
arr1[8] = 9; arr2[8] = 90;
arr1[9] = 11;arr2[9] = 100;

我需要通过如下排序将它们合并到第三个数组“arr3”中：

arr3 = [1,12,2,20,3,30,4,40,5,50,6,60,7,70,8,80,9,90,11,100]

这是我制作的代码，但它仍然无法正常工作：

#include <stdio.h>


int main(void) {
    int arr1[10], arr2[10], arr3[20], i,k,r;

    arr1[0] = 1; arr2[0] = 12; 
    arr1[1] = 2; arr2[1] = 20;
    arr1[2] = 3; arr2[2] = 30;
    arr1[3] = 4; arr2[3] = 40;
    arr1[4] = 5; arr2[4] = 50;
    arr1[5] = 6; arr2[5] = 60;
    arr1[6] = 7; arr2[6] = 70;
    arr1[7] = 8; arr2[7] = 80;
    arr1[8] = 9; arr2[8] = 90;
    arr1[9] = 11;arr2[9] = 100;

    for(i=0; i<20; i++){

        if(arr3[i-1] != 0){
            arr3[i] = arr1[i];
            arr3[i+1] = 0;
        } else {
            arr3[i-1] = arr2[i-1];
        }
        i++;

    }
    for(k=0; k<20; k++){
        printf("arr - %d b: %d \n", k, arr3[k]);
    }

    return 0;
}

Answer 1

尝试这个。

int i, j;
for (i = 0, j = 0; i < 10; i++) {
    arr3[j++] = arr1[i];
    arr3[j++] = arr2[i];
}

希望这可以帮助！:)