che*_*vim 11 java hibernate hibernate-mapping
我有User一个Log班级(我无法改变):
class User {
private long id;
private String name;
private Set<Log> accessLogs;
private Set<Log> actionLogs;
}
class Log {
private String what;
private Date when;
}
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可能的映射将如下所示:
<class name="com.example.User" table="users">
<id name="id" access="field">
<generator class="native" />
</id>
<property name="name" length="256" />
<set name="accessLogs" table="user_access_logs" cascade="all-delete-orphan" order-by="`when`">
<key column="user_id" />
<composite-element class="com.example.Log">
<property name="what" length="512" />
<property name="when" column="`when`" />
</composite-element>
</set>
<set name="actionLogs" table="user_action_logs" cascade="all-delete-orphan" order-by="`when`">
<key column="user_id" />
<composite-element class="com.example.Log">
<property name="what" length="512" />
<property name="when" column="`when`" />
</composite-element>
</set>
</class>
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这工作正常并映射到以下数据库表:
users
+----+------+
| id | name |
+----+------+
| 1 | john |
| 2 | bill |
| 3 | nick |
+----+------+
user_access_logs
+---------+------------+---------------------+
| user_id | what | when |
+---------+------------+---------------------+
| 1 | logged in | 2010-09-21 11:25:03 |
| 1 | logged out | 2010-09-21 11:38:24 |
| 1 | logged in | 2010-09-22 10:19:39 |
| 2 | logged in | 2010-09-22 11:03:18 |
| 1 | logged out | 2010-09-22 11:48:16 |
| 2 | logged in | 2010-09-26 12:45:18 |
+---------+------------+---------------------+
user_action_logs
+---------+---------------+---------------------+
| user_id | what | when |
+---------+---------------+---------------------+
| 1 | edit profile | 2010-09-21 11:28:13 |
| 1 | post comment | 2010-09-21 11:30:40 |
| 1 | edit profile | 2010-09-21 11:31:17 |
| 1 | submit link | 2010-09-22 10:21:02 |
| 2 | submit review | 2010-09-22 11:10:22 |
| 2 | submit link | 2010-09-22 11:11:39 |
+---------+---------------+---------------------+
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我的问题是如何在hibernate中将这两组(accessLogs和actionLogs)映射到同一个表中,为日志生成以下模式:
user_logs
+---------+---------------+---------------------+--------+
| user_id | what | when | type |
+---------+---------------+---------------------+--------+
| 1 | logged in | 2010-09-21 11:25:03 | access |
| 1 | edit profile | 2010-09-21 11:28:13 | action |
| 1 | post comment | 2010-09-21 11:30:40 | action |
| 1 | edit profile | 2010-09-21 11:31:17 | action |
| 1 | logged out | 2010-09-21 11:38:24 | access |
| 1 | logged in | 2010-09-22 10:19:39 | access |
| 1 | submit link | 2010-09-22 10:21:02 | action |
| 2 | logged in | 2010-09-22 11:03:18 | access |
| 2 | submit review | 2010-09-22 11:10:22 | action |
| 2 | submit link | 2010-09-22 11:11:39 | action |
| 1 | logged out | 2010-09-22 11:48:16 | access |
| 2 | logged in | 2010-09-26 12:45:18 | access |
+---------+---------------+---------------------+--------+
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编辑:我想保留Java代码和Set语义.我正在寻找像鉴别器,公式或hibernate API扩展这样的东西,它将解决这个问题,而无需触及Java代码.也许是顺便说一下(假想的hibernate配置如下):
<set name="accessLogs" table="user_logs" ... formula="type='access'">
<key column="user_id" />
<composite-element class="Log">
...
</composite-element>
</set>
<set name="actionLogs" table="user_logs" ... formula="type='action'">
<key column="user_id" />
<composite-element class="Log">
...
</composite-element>
</set>
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编辑2:我还没有完整的解决方案.我确信它可以通过扩展一些hibernate API来完成.
Mau*_*ara 11
您是否尝试以这种方式映射集:
<set name="accessLogs" table="user_logs" where="type='access'">
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正如Maurizio所写,您需要使用该where属性来仅检索属于每个集合的行.
要使用附加列插入行,您需要在以下内容中添加以下元素<set>:
<sql-insert>
insert into user_logs(user_id, what, [when], type)
values(?, ?, ?, 'access')
</sql-insert>
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这基本上告诉Hibernate使用特定的SQL而不是生成它.请注意,我必须手动转义when列.
额外:要将额外列添加到数据库,请使用以下(关闭后<class>)
<database-object>
<create>alter table user_logs add type char(6)</create>
<drop></drop>
</database-object>
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有趣的一点:我使用NHibernate编写并测试了它,但它是直接移植的,所以它应该完全相同.
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