条件xml序列化

Question

我有以下C#类:

public class Books
{

public List<Book> BookList;

}

public class Book
{

public string Title;
public string Description;
public string Author;
public string Publisher;

}

如何将此类序列化为以下XML？

<Books>
  <Book Title="t1" Description="d1"/>
  <Book Description="d2" Author="a2"/>
  <Book Title="t3" Author="a3" Publisher="p3"/>
</Books>

我希望XML只包含那些值为null/empty的属性.例如:在第一个Book元素中,author是空白的,因此它不应出现在序列化XML中.

Answer 1

你应该能够使用这种ShouldSerialize*模式:

public class Book
{
    [XmlAttribute] 
    public string Title {get;set;}

    public bool ShouldSerializeTitle() {
        return !string.IsNullOrEmpty(Title);
    }

    [XmlAttribute]
    public string Description {get;set;}

    public bool ShouldSerializeDescription() {
        return !string.IsNullOrEmpty(Description );
    }

    [XmlAttribute]
    public string Author {get;set;}

    public bool ShouldSerializeAuthor() {
        return !string.IsNullOrEmpty(Author);
    }

    [XmlAttribute]
    public string Publisher {get;set;}

    public bool ShouldSerializePublisher() {
        return !string.IsNullOrEmpty(Publisher);
    }
}

Answer 2

替代方案

• 将您的公共字段切换到属性
• 使用DefaultValueAttribute属性定义默认值
• 使用ContentPropertyAttribute属性定义content 属性
• 使用XamlWriter/XamlReader

你最终得到这样的东西:

 [ContentProperty("Books")]
 public class Library {

   private readonly List<Book> m_books = new List<Book>();

   public List<Book> Books { get { return m_books; } }

 }

 public class Book
 {

    [DefaultValue(string.Empty)]
    public string Title { get; set; }

    [DefaultValue(string.Empty)]
    public string Description { get; set; }

    [DefaultValue(string.Empty)]
    public string Author { get; set; }

 }