我有以下XML:
<LOCALCELL_V18 ID = "0x2d100000">
<MXPWR ID = "0x3d1003a0">100</MXPWR>
</LOCALCELL_V18>
<LOCALCELL_V18 ID = "0x2d140000">
<MXPWR ID = "0x3d1403a0">200</MXPWR>
</LOCALCELL_V18>
<LOCALCELL_V18 ID = "0x2d180000">
<MXPWR ID = "0x3d1803a0">300</MXPWR>
</LOCALCELL_V18>
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我想得到每个的内在文本<MXPWR>.但是,不允许使用ID#来定位内部文本,因为它并不总是相同的.这是我的代码:
XmlNodeList LocalCell = xmlDocument.GetElementsByTagName("LOCALCELL_V18");
foreach (XmlNode LocalCell_Children in LocalCell)
{
XmlElement MXPWR = (XmlElement)LocalCell_Children;
XmlNodeList MXPWR_List = MXPWR.GetElementsByTagName("MXPWR");
for (int i = 0; i < MXPWR_List.Count; i++)
{
MaxPwr_form_str = MXPWR_List[i].InnerText;
}
}
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任何意见将不胜感激.
我会用xpath.它专为此类问题而设计.就像是:
using System.Xml;
using System.Xml.XPath;
....
string fileName = "data.xml"; // your file here
XPathDocument doc = new XPathDocument(fileName);
XPathNavigator nav = doc.CreateNavigator();
// Compile an xpath expression
XPathExpression expr = nav.Compile("./LOCALCELL_V18/MXPWR");
XPathNodeIterator iterator = nav.Select(expr);
// Iterate on the node set
while (iterator.MoveNext())
{
string s = iterator.Current.Value;
}
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当我在你的XML文件上运行它(包装在根节点中)时,我得到:
s = 100
s = 200
s = 300
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我会使用XLinq:
using System.Xml.Linq;
var xDoc = XDocument.Load("data.xml");
var mxpwrs = xDoc.Descendants("MXPWR");
foreach (var mxpwr in mxpwrs)
{
Console.WriteLine(mxpwr.Value);
}
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