C++ If/else/nesting问题

Question

我正在尝试学习c ++,我遇到了if/else语句的问题.当我在没有打开和关闭牙箍的情况下筑巢时,我以为我把它们弄下来了,但是我试着用牙箍来解决问题.

有人可以指出错误以及如何解决它,而不仅仅是答案; 这样我就不会学到东西了.

这是我的来源:

#include "stdafx.h"
#include <iostream>
using namespace std;

int main()
{
 signed long int RealNumber = 31710;
 int Guess;

 cout << "Lets see if you can guess my favorite number... \n";
 cout << "Type in a number and hit enter to see if you have guessed it correctly. \n";
 cout << "you should know this one Danielle. \n \n ";
 cin >> Guess;


 if (Guess == RealNumber)
 {
  cout << "Wow, you are amazing! \n";
  cout << "Would you like to be punched?";
 }
 else
 {
  if (Guess < RealNumber)
   cout << "The number is higher";
  else
   if (Guess > RealNumber)
    cout << "The number is lower";
   else
    cout << "That is impossible!"; //trying to make sure that if anthing but a number is entered that the program doesn't crash.
 }

}
 char f;  // used to make the program wait for input before closing. 
 cin >> f;

 return 0;

Answer 1

你的线上方有一个额外的支架,上面写着 -

char f; 
cin >> f; 

这个右括号匹配你的主要功能的初始大括号.

你在if/else嵌套中使用的支撑结构对我来说似乎很好.

这是一个提示 - 对于每个左括号,立即键入右括号,并添加注释.你不必永远使用这个'拐杖',但作为一个学习编写代码的初学者,这个coudl非常有帮助.

步骤1:

int main()
{
}//main 

第2步:

int main()
{
    int foo; 
    cin >> foo; 
    if (foo < 100)
    {
        //todo 
    }// if (foo < 100)
}//main

第3步:

int main()
{
    int foo; 
    cin >> foo; 
    if (foo < 100)
    {
        cout << "foo is too small";
        cin >> foo; 
        if (foo < 100)
        {
            //todo 
        } // if (foo < 100), inner if statement 
    }// if (foo < 100)
}//main

等等