Sau*_*man 2 c++ if-statement conditional-operator conditional-statements
我似乎无法获得这些if语句按预期工作.无论我输入"字符串答案",它总是跳转到第一个IF语句,其中条件设置为仅在答案正好为"n"或"N"时执行块或者答案恰好为"y"的块或"Y".如果你输入任何其他内容,它应该返回0.
// Game Recap function, adds/subtracts player total, checks for deposit total and ask for another round
int gameRecap() {
string answer;
answer.clear();
cout << endl << "---------------" << endl;
cout << "The winner of this Game is: " << winner << endl;
cout << "Player 1 now has a total deposit of: " << deposit << " credits remaining!" << endl;
cout << "-------------------------" << endl;
if (deposit < 100) {
cout << "You have no remaining credits to play with" << endl << "Program will now end" << endl;
return 0;
}
else if (deposit >= 100) {
cout << "Would you like to play another game? Y/N" << endl;
cin >> answer;
if (answer == ("n") || ("N")) {
cout << "You chose no" << endl;
return 0;
}
else if (answer == ("y") || ("Y")) {
cout << "You chose YES" << endl;
currentGame();
}
else {
return 0;
}
return 0;
}
else {
return 0;
}
return 0;
}
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这不正确:
if (answer == ("n") || ("N"))
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它应该是
if (answer == "n" || answer == "N")
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找出当前代码编译的原因是有益的:在C++和C中,隐式!= 0被添加到不表示布尔表达式的条件中.因此,表达式的第二部分变为
"N" != 0
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总是true:"N"是一个字符串文字,永远不会NULL.
该||运营商不工作,你似乎认为它的方式.
if (answer == ("n") || ("N"))
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正在检查是否answer是"n",如果不是,它正在评估"N"为布尔值,在这种情况下始终为真.你真正想做的是
if (answer == ("n") || answer == ("N"))
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你也应该做类似调整针对检查"y"和"Y".