我有一个大的data.table,结构类似于df:
library("data.table")
df <- data.frame(part = c("A", "B", "A", "C", "A", "D", "B", "D", "E"),
day = c(1, 2, 3, 4, 5, 6, 6, 7, 15),
code = c("S", "S", "P", "X", "P", "S", "P", "P", "P"))
setDT(df)
df
part day code
1: A 1 S
2: B 2 S
3: A 3 P
4: C 4 X
5: A 5 P
6: D 6 S
7: B 6 P
8: D 7 P
9: E 15 P
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我怎样才能增加一列,标记记录,其中code= S和同样part具有code= P在3以后的日子里?预期结果:
part day code flag
1: A 1 S TRUE
2: B 2 S FALSE
3: A 3 P FALSE
4: C 4 X FALSE
5: A 5 P FALSE
6: D 6 S TRUE
7: B 6 P FALSE
8: D 7 P FALSE
9: E 15 P FALSE
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我认为这样做
df[, v := FALSE ]
df[code == "S", v := !is.na(
df[code == "P"][df[code == "S"], on=c("part", "day"), roll=-3, which=TRUE]
)]
part day code v
1: A 1 S TRUE
2: B 2 S FALSE
3: A 3 P FALSE
4: C 4 X FALSE
5: A 5 P FALSE
6: D 6 S TRUE
7: B 6 P FALSE
8: D 7 P FALSE
9: E 15 P FALSE
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它是如何工作的 !is.na(x[i, which=TRUE])告诉我们每一行是否i找到匹配x.(如果i找到多个匹配项,这可能会分解.)该roll部分扩展了匹配范围,以覆盖最后一列所连接的行on.
我不确定那里的roll值是否正确,因为我从未使用过这种方式.