Joa*_*iay 1 python datetime date pandas
我有这种包含 9000 行的字符串列表,其中每一行是月/日/年:
10/30/2009
12/19/2009
4/13/2009
8/18/2007
7/17/2008
6/16/2009
1/14/2009
12/18/2007
9/14/2009
2/13/2006
3/25/2009
2/23/2007
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我想转换它,如果有可能作为日期格式,则只有带有月/年的列表,如下所示:
10/2009
12/2009
4/2009
8/2007
7/2008
6/2009
1/2009
12/2007
9/2009
2/2006
3/2009
2/2007
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我认为你可以先使用to_datetime,然后to_period:
df.col = pd.to_datetime(df.col).dt.to_period('m')
print (df)
col
0 2009-10
1 2009-12
2 2009-04
3 2007-08
4 2008-07
5 2009-06
6 2009-01
7 2007-12
8 2009-09
9 2006-02
10 2009-03
11 2007-02
print (type(df.loc[0,'col']))
<class 'pandas._period.Period'>
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或者strftime:
df.col = pd.to_datetime(df.col).dt.strftime('%m/%Y')
print (df)
col
0 10/2009
1 12/2009
2 04/2009
3 08/2007
4 07/2008
5 06/2009
6 01/2009
7 12/2007
8 09/2009
9 02/2006
10 03/2009
11 02/2007
print (type(df.loc[0,'col']))
<class 'str'>
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或replace通过regex:
df.col = df.col.str.replace('/.+/','/')
print (df)
col
0 10/2009
1 12/2009
2 4/2009
3 8/2007
4 7/2008
5 6/2009
6 1/2009
7 12/2007
8 9/2009
9 2/2006
10 3/2009
11 2/2007
print (type(df.loc[0,'col']))
<class 'str'>
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