将数据从fstream复制到stringstream而没有缓冲区？

Question

无论如何我可以将数据从fstream(一个文件)传输到stringstream(内存中的流)吗？

目前,我正在使用缓冲区,但这需要双倍的内存,因为您需要将数据复制到缓冲区,然后将缓冲区复制到字符串流,直到您删除缓冲区,数据在内存中重复.

std::fstream fWrite(fName,std::ios::binary | std::ios::in | std::ios::out);  
    fWrite.seekg(0,std::ios::end); //Seek to the end  
    int fLen = fWrite.tellg(); //Get length of file  
    fWrite.seekg(0,std::ios::beg); //Seek back to beginning  
    char* fileBuffer = new char[fLen];  
    fWrite.read(fileBuffer,fLen);  
    Write(fileBuffer,fLen); //This writes the buffer to the stringstream  
    delete fileBuffer;`

有没有人知道如何在不使用inbetween缓冲区的情况下将整个文件写入字符串流？

Answer 1

// need to include <algorithm> and <iterator>, and of course <fstream> and <sstream>
ifstream fin("input.txt");
ostringstream sout;
copy(istreambuf_iterator<char>(fin),
     istreambuf_iterator<char>(),
     ostreambuf_iterator<char>(sout));

Answer 2

 ifstream f(fName);
 stringstream s;
 if (f) {
     s << f.rdbuf();    
     f.close();
 }

Answer 3

在文档中ostream,有几个重载operator<<.其中一个接受streambuf*并读取所有streambuffer的内容.

这是一个示例用法(编译和测试):

#include <exception>
#include <iostream>
#include <fstream>
#include <sstream>

int main ( int, char ** )
try
{
        // Will hold file contents.
    std::stringstream contents;

        // Open the file for the shortest time possible.
    { std::ifstream file("/path/to/file", std::ios::binary);

            // Make sure we have something to read.
        if ( !file.is_open() ) {
            throw (std::exception("Could not open file."));
        }

            // Copy contents "as efficiently as possible".
        contents << file.rdbuf();
    }

        // Do something "useful" with the file contents.
    std::cout << contents.rdbuf();
}
catch ( const std::exception& error )
{
    std::cerr << error.what() << std::endl;
    return (EXIT_FAILURE);
}