Ric*_*ook 4 haskell numpy hmatrix
是否有一个标准的Haskell等同于NumPy的argsort功能?
我正在使用HMatrix,因此,希望兼容的功能Vector R是别名Data.Vector.Storable.Vector Double.argSort下面的函数是我目前使用的实现:
{-# LANGUAGE NoImplicitPrelude #-}
module Main where
import qualified Data.List as L
import qualified Data.Vector as V
import qualified Data.Vector.Storable as VS
import Prelude (($), Double, IO, Int, compare, print, snd)
a :: VS.Vector Double
a = VS.fromList [40.0, 20.0, 10.0, 11.0]
argSort :: VS.Vector Double -> V.Vector Int
argSort xs = V.fromList (L.map snd $ L.sortBy (\(x0, _) (x1, _) -> compare x0 x1) (L.zip (VS.toList xs) [0..]))
main :: IO ()
main = print $ argSort a -- yields [2,3,1,0]
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我正在使用显式限定的imports来明确每个类型和函数的来源.
此实现不是非常有效,因为它将输入向量转换为列表并将结果转换回向量.在某个地方存在这样的事情(但效率更高)?
更新
@leftaroundabout有一个很好的解决方案.这是我最终得到的解决方案:
module LAUtil.Sorting
( IndexVector
, argSort
)
where
import Control.Monad
import Control.Monad.ST
import Data.Ord
import qualified Data.Vector.Algorithms.Intro as VAI
import qualified Data.Vector.Storable as VS
import qualified Data.Vector.Unboxed as VU
import qualified Data.Vector.Unboxed.Mutable as VUM
import Numeric.LinearAlgebra
type IndexVector = VU.Vector Int
argSort :: Vector R -> IndexVector
argSort xs = runST $ do
let l = VS.length xs
t0 <- VUM.new l
forM_ [0..l - 1] $
\i -> VUM.unsafeWrite t0 i (i, (VS.!) xs i)
VAI.sortBy (comparing snd) t0
t1 <- VUM.new l
forM_ [0..l - 1] $
\i -> VUM.unsafeRead t0 i >>= \(x, _) -> VUM.unsafeWrite t1 i x
VU.freeze t1
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Numeric.LinearAlgebra由于数据向量是a,因此更直接可用Storable.这为索引使用了未装箱的矢量.
使用矢量算法:
import Data.Ord (comparing)
import qualified Data.Vector.Unboxed as VU
import qualified Data.Vector.Algorithms.Intro as VAlgo
argSort :: (Ord a, VU.Unbox a) => VU.Vector a -> VU.Vector Int
argSort xs = VU.map fst $ VU.create $ do
xsi <- VU.thaw $ VU.indexed xs
VAlgo.sortBy (comparing snd) xsi
return xsi
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注意这些Unboxed不是Storable矢量.后者需要做出一些权衡以允许不纯的C FFI操作,并且无法正确处理异构元组.你当然可以总是convert来往于可存储的载体.