如何在sequelize中选择案例查询？

Question

我有一个SQL查询:

SELECT field1, field2,
  CASE
    WHEN field1=1 THEN 'a'
    ELSE 'b'
  END 
  AS field3
FROM test

我想用它实现它sequelizejs,

const params = {
  attributes: //DO SELECT CASE,
};

yield Model.findAll(params);

谁能帮我？谢谢.

Answer 1

对于仍在寻找这个答案的人们

Model.findAll({
  attributes: [[models.sequelize.literal('CASE WHEN "field1" = true THEN 55 ELSE 23 END'), 'field3']]
}

要么

Model.findAll({
  attributes: { include: [[models.sequelize.literal('CASE WHEN "field1" = true THEN 55 ELSE 23 END'), 'field3']]}
}

所以在我的例子中,当field1为true时,它将返回55 else 23.这将生成一个类似的查询

SELECT CASE WHEN "field1" THEN 55 ELSE 23 END AS "field3" FROM "models"

有关详细信息,请参阅文档 http://docs.sequelizejs.com/en/latest/docs/querying/#attributes