RxJava主题在不正确的调度程序上发出

bak*_*kua 3 multithreading android scheduler subject rx-java

我有一个以下课程,我作为一个单身人士持有:

public class SessionStore {
    Subject<Session, Session> subject;

    public SessionStore() {
       subject = new SerializedSubject<>(BehaviorSubject.create(new Session());
    }

    public void set(Session session) {
        subject.onNext(session);
    }

    public Observable<UserSession> observe() {
        return subject.distinctUntilChanged();
    }
}
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在活动中,我观察会话并对每次更改执行网络操作:

private Subscription init() {
    return sessionStore
            .observe()
            .subscribeOn(Schedulers.io())
            .observeOn(AndroidSchedulers.mainThread())
            .flatMap(new Func1<Session, Observable<Object>>() {
                @Override
                public Observable<Object> call(Session session) {
                    return retrofitService.getAThing();
                }
            })
            .subscribe(...);
}
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当我订阅会话存储时,主题io()立即发出,因为它是a BehaviourSubject并且订阅者执行mainThread().

当我sessionStore.set(new AnotherSession())在已经订阅它的时候打电话的时候会出现问题.IMO这应该执行init()io()调度程序中定义的流.然而,发生的是流在subject.onNext()被调用的同一线程上执行.导致成NetworkOnMainThreadException,因为我在做一个网络操作flatMap().

我是否理解主题错了?我这样滥用他们吗?那么适当的解决方案是什么?

我也尝试用Observable.fromEmitter()in observe()方法替换整个主题方法,但令人惊讶的是输出结果非常相似.

Han*_*rst 7

请看看下面的部分从书" 响应式编程方面RxJava "

默认情况下,在Subject上调用onNext()会直接传播到所有Observer的onNext()回调方法.这些方法具有相同的名称并不奇怪.在某种程度上,在Subject上调用onNext()会在每个Subscriber上间接调用onNext().

让我们回顾一下:如果从Thread-1调用Subject上的onNext,它将从Thread-1调用onNext到订阅者.onSubscribe将被删除.

首先要做的事情是:订阅发生在哪个线程上:

retrofitService.getAThing()
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我会猜测,并说它是调用线程.这将是observeOn中描述的线程,它是Android-UI-Loop.

observeOn下的每个值都将从调度程序指定的Thread-a转移到Thread-b.UI-Loop上的observeOn应该在订阅之前发生.订阅中将接收的每个值都将位于UI-Loop上,这不会阻止UI线程或以异常结束.

Pease看一下示例代码和输出:

class SessionStore {
    private Subject<String, String> subject;

    public SessionStore() {
        subject = BehaviorSubject.create("wurst").toSerialized();
    }

    public void set(String session) {
        subject.onNext(session);
    }

    public Observable<String> observe() {
        return subject
                .asObservable()
                .doOnNext(s -> System.out.println("Receiving value on Thread:: " + Thread.currentThread()))
                .distinctUntilChanged();
    }
}

@Test
public void name() throws Exception {
    // init
    SessionStore sessionStore = new SessionStore();

    TestSubscriber testSubscriber = new TestSubscriber();
    Subscription subscribe = sessionStore
            .observe()
            .flatMap(s -> {
                return Observable.fromCallable(() -> {
                    System.out.println("flatMap Thread:: " + Thread.currentThread());
                    return s;
                }).subscribeOn(Schedulers.io());
            })
            .doOnNext(s -> System.out.println("After flatMap Thread:: " + Thread.currentThread()))
            .observeOn(Schedulers.newThread()) // imagine AndroidScheduler here
            .subscribe(testSubscriber); // Do UI-Stuff in subscribe

    new Thread(() -> {
        System.out.println("set on Thread:: " + Thread.currentThread());
        sessionStore.set("123");
    }).start();

    new Thread(() -> {
        System.out.println("set on Thread:: " + Thread.currentThread());
        sessionStore.set("345");
    }).start();

    boolean b = testSubscriber.awaitValueCount(3, 3_000, TimeUnit.MILLISECONDS);

    Assert.assertTrue(b);
}
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输出::

Receiving value on Thread:: Thread[main,5,main]
flatMap Thread:: Thread[RxIoScheduler-2,5,main]
After flatMap Thread:: Thread[RxIoScheduler-2,5,main]
set on Thread:: Thread[Thread-1,5,main]
set on Thread:: Thread[Thread-0,5,main]
Receiving value on Thread:: Thread[Thread-1,5,main]
flatMap Thread:: Thread[RxIoScheduler-2,5,main]
After flatMap Thread:: Thread[RxIoScheduler-2,5,main]
Receiving value on Thread:: Thread[Thread-1,5,main]
flatMap Thread:: Thread[RxIoScheduler-2,5,main]
After flatMap Thread:: Thread[RxIoScheduler-2,5,main]
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