Kar*_*elė 7 python inheritance
我有一个抽象类,有三个方法是等同的意义 - 它们都可以使用一些昂贵的转换函数相互定义.我希望能够编写一个派生类,只需要覆盖其中一个方法并自动获取另外两个方法.例
class FooBarBaz(object):
def foo(self, x):
return foo_from_bar(self.bar(x))
# OR return foo_from_baz(self.baz(x))
def bar(self, x):
return bar_from_foo(self.foo(x))
# OR return bar_from_baz(self.baz(x))
def baz(self, x):
return baz_from_bar(self.bar(x))
# OR return baz_from_foo(self.foo(x))
class Derived1(FooBarBaz):
def bar(self, x):
return 5
# at this point foo = foo_from_bar(5) and
# baz = baz_from_bar(5), which is what I wanted
class Derived2(FooBarBaz):
def foo(self, x):
return 6
# at this point bar = bar_from_foo(6) and
# baz = baz_from_bar(bar_from_foo(6)),
# which is not ideal, but still works
class Derived3(FooBarBaz):
def baz(self, x):
return 7
# at this point foo and bar remain defined
# in terms of each other, which is a PROBLEM
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我知道我可以明确地告诉每个派生类要使用哪些转换.我想知道父类是否有办法自行解决这个问题,而不修改子项.
您可以诉诸元编程技术,例如编写一个自动填充剩余方法的元类,或者使用内省依次查看这些类type(self).mro()以找出哪些方法已被覆盖。然而,这些选项对我来说完全属于“太多魔法”类别,所以我会选择更简单的东西。
只需将每个方法分为两部分:一个是通用方法,另一个是实际实现。派生类覆盖实际实现:
class FooBarBaz(object):
def foo_impl(self, x):
raise NotImplementedError
def foo(self, x):
try:
return self.foo_impl(x)
except NotImplementedError:
try:
return foo_from_bar(self.bar_impl(x))
except NotImplementedError:
return foo_from_baz(self.baz_impl(x))
# Similarly fo bar and baz
class Dervied(FooBarBaz):
def bar_impl(self, x):
return 5
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通用逻辑也可以在装饰器中分解:
def first_implemented(func):
@functools.wraps
def wrapper(*args, **kwargs):
for f in func(*args, **kwargs):
try:
return f()
except NotImplementedError:
pass
raise NotImplementedError
return wrapper
class FooBarBaz(object):
def foo_impl(self, x):
raise NotImplementedError
@first_implemented
def foo(self, x):
yield lambda: self.foo_impl(x)
yield lambda: foo_from_bar(self.bar_impl(x))
yield lambda: foo_from_baz(self.baz_impl(x))
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