如何使用xml Body发送带有alamofire的请求

Question

我在我的项目中安装了Alamofire,现在这就是我所做的.

我安装了邮差,我把我的网址和内部的一个xml对象,我得到了我的结果.

这是我对邮递员所做的一切

我现在如何使用Alamofire或SWXMLHash发送它,因为我发送邮件

提前致谢!

编辑

我从另一个问题尝试了这个:

 Alamofire.request(.POST, "https://something.com" , parameters: Dictionary(), encoding: .Custom({
            (convertible, params) in
            let mutableRequest = convertible.URLRequest.copy() as! NSMutableURLRequest

            let data = (self.testString as NSString).dataUsingEncoding(NSUTF8StringEncoding)
            mutableRequest.HTTPBody = data
            return (mutableRequest, nil)
        }))


    .responseJSON { response in


    print(response.response) 

    print(response.result)   


    }
}

但它没有发送任何东西

这是日志:

可选({URL:https: //something.com } {状态代码:200,headers {Connection ="keep-alive";"Content-Length"= 349;"Content-Type"="application/xml";日期="Wed,2016年11月2日21:13:32 GMT"; Server = nginx;"Strict-Transport-Security"="max-age = 31536000; includeSubDomains";}})

失败

编辑

如果没有简单的添加,请不要忘记参数参数:参数:Dictionary()

Answer 1

使用Swift 3和Alamofire 4

    let stringParams : String = "<msg id=\"123123\" reqTime=\"123123\">" +
        "<params class=\"API\">" + 
        "<param name=\"param1\">123213</param>" + 
        "<param name=\"param2\">1232131</param>" +
        "</params>" +
    "</msg>"

    let url = URL(string:"<#URL#>")
    var xmlRequest = URLRequest(url: url!)
    xmlRequest.httpBody = stringParams.data(using: String.Encoding.utf8, allowLossyConversion: true)
    xmlRequest.httpMethod = "POST"
    xmlRequest.addValue("application/xml", forHTTPHeaderField: "Content-Type")


    Alamofire.request(xmlRequest)
            .responseData { (response) in
                let stringResponse: String = String(data: response.data!, encoding: String.Encoding.utf8) as String!
                debugPrint(stringResponse)
    }

Answer 2

使用 Swift 3 和 Alamofire 4，您可以创建自定义ParameterEncoding. 与任何其他 XML 编码主体一样，SOAP 消息可以使用此参数编码，如下例所示。可以类似地创建其他 XML 正文编码（检查它说的行urlRequest.httpBody = ...）：

struct SOAPEncoding: ParameterEncoding {
    let service: String
    let action: String

    func encode(_ urlRequest: URLRequestConvertible, with parameters: Parameters?) throws -> URLRequest {
        var urlRequest = try urlRequest.asURLRequest()

        guard let parameters = parameters else { return urlRequest }

        if urlRequest.value(forHTTPHeaderField: "Content-Type") == nil {
            urlRequest.setValue("text/xml", forHTTPHeaderField: "Content-Type")
        }

        if urlRequest.value(forHTTPHeaderField: "SOAPACTION") == nil {
            urlRequest.setValue("\(service)#\(action)", forHTTPHeaderField: "SOAPACTION")
        }

        let soapArguments = parameters.map({key, value in "<\(key)>\(value)</\(key)>"}).joined(separator: "")

        let soapMessage =
            "<s:Envelope xmlns:s='http://schemas.xmlsoap.org/soap/envelope/' s:encodingStyle='http://schemas.xmlsoap.org/soap/encoding/'>" +
            "<s:Body>" +
            "<u:\(action) xmlns:u='\(service)'>" +
            soapArguments +
            "</u:\(action)>" +
            "</s:Body>" +
            "</s:Envelope>"

        urlRequest.httpBody = soapMessage.data(using: String.Encoding.utf8)

        return urlRequest
    }
}

然后像这样使用它：

Alamofire.request(url, method: .post, parameters: ["parameter" : "value"], encoding: SOAPEncoding(service: "service", action: "action"))