将 dict 对象转换为嵌套列表

use*_*642 1 python python-3.x

我正在寻找如何从字典创建嵌套列表。这是给定的字典。

Dict={'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'], 'Kenneth Love': ['Python Basics', 'Python Collections'],'Jason Bourne':['black berry','mango','potato','oli','key'],'fruits':['cherry','pineapple','banana','coconut']}
Run Code Online (Sandbox Code Playgroud)

异常输出:

[['Jason Bourne', 5], ['Kenneth Love', 2], ['fruits', 4], ['Jason Seifer', 3]]
Run Code Online (Sandbox Code Playgroud)

这里顺序并不重要

Tig*_*kT3 5

简单理解一下:

result = [[k, len(v)] for k,v in Dict.items()]
Run Code Online (Sandbox Code Playgroud)