将数组动态转换为树状结构

Dre*_* XD 5 javascript arrays

有人能告诉我将数组转换为树状结构的最有效方法吗?

var array= [
        {id: "1",     name: "header1"},
        {id: "2",     name: "header2"},
        {id: "1.1",   name: "subheader1.1"},
        {id: "1.2",   name: "subheader1.2"},
        {id: "2.1",   name: "subheader2.1"},
        {id: "2.2",   name: "subheader2.2"},
        {id: "1.1.1", name: "subheader1detail1"},
        {id: "2.1.1", name: "subheader2detail2"}
];
Run Code Online (Sandbox Code Playgroud)

结果数组必须如下:

var array = [{
    id: "1",
    name: "header1",
    items: [{
        id: "1.1",
        name: "subheader1.1",
        items: [{
            id: "1.1.1",
            name: "subheader1detail1",
        }]
    }, {
        id: "1.2",
        name: "subheader1.2"
    }]
}, {
    id: "2",
    name: "header2",
    items: [{
        id: "2.1",
        name: "subheader2.1",
        items: [{
            id: "2.1.1",
            name: "subheader2detail2",
        }]
    }, {
        id: "2.2",
        name: "subheader2.2"
    }]
}]
Run Code Online (Sandbox Code Playgroud)

提前致谢

Nin*_*olz 5

您可以使用一棵树并在其上构建嵌套数组。该提案需要一个排序列表。

基本上,它查找节点的父节点,如果节点没有父节点,则找到根节点并将其插入到结果数组中。如果找到父节点,则将实际节点插入到items父节点的属性中。

var array = [{ id: "1", name: "header1" }, { id: "2", name: "header2" }, { id: "1.1", name: "subheader1.1" }, { id: "1.2", name: "subheader1.2" }, { id: "2.1", name: "subheader2.1" }, { id: "2.2", name: "subheader2.2" }, { id: "1.1.1", name: "subheader1detail1" }, { id: "2.1.1", name: "subheader2detail2" }],
    result = [];

array.forEach(function (a) {
    var parent = a.id.split('.').slice(0, -1).join('.');

    this[a.id] = { id: a.id, name: a.name };
    if (parent) {
        this[parent] = this[parent] || {};
        this[parent].items = this[parent].items || [];
        this[parent].items.push(this[a.id]);
    } else {
        result.push(this[a.id]);
    }
}, {});

console.log(result);
Run Code Online (Sandbox Code Playgroud)
.as-console-wrapper { max-height: 100% !important; top: 0; }
Run Code Online (Sandbox Code Playgroud)

  • 你让事情看起来如此简单!只是一个小指针,您应该对数组未排序的任何情况进行排序。休息真是哇! (3认同)