Swift:在Switch语句中使用比较运算符

Ste*_*nez 4 switch-statement swift

我正在尝试创建一个Switch语句(Swift),当case大于给定数字时返回一个String.我知道这可以通过"if"或"else if"语句完成,但我希望用Switch语句来完成这个.可以这样做还是Switch语句无法使用"大于"比较运算符?

var score = 101
var letterGrade = ""

switch score{
    case >100:
    letterGrade = "A+ With Extra Credit"
case 90...100:
    letterGrade = "A"
case 80...89:
    letterGrade = "B"
case 70...79:
    letterGrade = "C"
case 60...69:
    letterGrade = "D"
default:
    letterGrade = "Incomplete"
}
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Mag*_*ios 9

是一个简单的解决方案,将它绑定到这样的常量:

    var score = 101
var letterGrade = ""

switch score{
case let x where x > 100:
    letterGrade = "A+ With Extra Credit"
case 90...100:
    letterGrade = "A"
case 80...89:
    letterGrade = "B"
case 70...79:
    letterGrade = "C"
case 60...69:
    letterGrade = "D"
default:
    letterGrade = "Incomplete"
}
Run Code Online (Sandbox Code Playgroud)

这完全符合您的需要