bla*_*ite 4 python types infinity scikit-learn
k我正在尝试根据使用的轮廓分数找到正确的簇数sklearn.cluster.MiniBatchKMeans。
from sklearn.cluster import MiniBatchKMeans
from sklearn.feature_extraction.text import HashingVectorizer
docs = ['hello monkey goodbye thank you', 'goodbye thank you hello', 'i am going home goodbye thanks', 'thank you very much sir', 'good golly i am going home finally']
vectorizer = HashingVectorizer()
X = vectorizer.fit_transform(docs)
for k in range(5):
model = MiniBatchKMeans(n_clusters = k)
model.fit(X)
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我收到此错误:
Warning (from warnings module):
File "C:\Python34\lib\site-packages\sklearn\cluster\k_means_.py", line 1279
0, n_samples - 1, init_size)
DeprecationWarning: This function is deprecated. Please call randint(0, 4 + 1) instead
Traceback (most recent call last):
File "<pyshell#85>", line 3, in <module>
model.fit(X)
File "C:\Python34\lib\site-packages\sklearn\cluster\k_means_.py", line 1300, in fit
init_size=init_size)
File "C:\Python34\lib\site-packages\sklearn\cluster\k_means_.py", line 640, in _init_centroids
x_squared_norms=x_squared_norms)
File "C:\Python34\lib\site-packages\sklearn\cluster\k_means_.py", line 88, in _k_init
n_local_trials = 2 + int(np.log(n_clusters))
OverflowError: cannot convert float infinity to integer
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我知道这个type(k)问题int,所以我不知道这个问题来自哪里。我可以很好地运行以下命令,但我似乎无法迭代列表中的整数,即使type(2)等于k = 2; type(k)
model = MiniBatchKMeans(n_clusters = 2)
model.fit(X)
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甚至运行不同的model作品:
>>> model = KMeans(n_clusters = 2)
>>> model.fit(X)
KMeans(copy_x=True, init='k-means++', max_iter=300, n_clusters=2, n_init=10,
n_jobs=1, precompute_distances='auto', random_state=None, tol=0.0001,
verbose=0)
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让我们分析一下您的代码:
for k in range(5)返回以下序列:
0, 1, 2, 3, 4model = MiniBatchKMeans(n_clusters = k)初始化模型n_clusters=kn_clusters=0用来int(np.log(n_clusters))int(np.log(0))int(-inf)设置n_clusters=0没有意义!
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