Not*_*Dan 4 ruby ruby-on-rails
我有一个帐户列表,我想保存为YAML文件并将其加载到ruby中.像这样的东西:
Run Code Online (Sandbox Code Playgroud)Account1 John Smith jsmith jsmith@gmail.com Account2 John Doe jdoe jdoe@hotmail.com
然后我想获得名为"John Doe"的人的电子邮件地址(例如).
我该怎么做呢?
age*_*217 10
在这里,您将yaml对象保存为Person对象,然后在加载它们时,它们将加载到Person对象中,使它们更容易处理.
首先将你的yaml文件调整为这样的:
---
- !ruby/object:Person
name: John Doe
sname: jdoe
email: jdoe@gmail.com
- !ruby/object:Person
name: Jane Doe
sname: jdoe
email: jane@hotmail.com
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现在,您可以将yaml文件加载到Person对象数组中,然后操作数组:
FILENAME = 'data.yaml'
class Person
attr_accessor :name, :sname, :email
end
require "yaml"
# Will return an array of Person objects.
data = YAML::load(File.open(FILENAME))
# Will print out the first object in the array's name. #=> John Doe
puts data.first.name
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