Cre*_*er7 7 javascript ecmascript-5 ecmascript-6
我正在尝试编写一个函数,该函数根据日期是否存在于数组中而返回TRUE或FALSE值.目前我有这个:
function isInArray(value, array) {
var a = array.indexOf(value) > -1;
if (a == false) {
return false; //DATE DOES NOT EXIST
}
else {
return true; //DATE EXISTS IN ARRAY
}
}
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现在通常我会使用for循环,但是我使用while循环生成开始日期和结束日期之间的日期列表:
while (day > 0) {
var tDate = new Date(sDate.addDays(dayCounter));
datesArray.push(tDate);
day = day - 1; //DEDUCT THE DAYS AS ADDED
var dateExists = isInArray(value, array);
if (dateExists == false) {
}
else {
matchedDays++;
}
daysCounter++;
}
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然而,这不起作用并且总是返回FALSE,我需要做什么才能使这个工作并返回正确的值?
样本数据: ARRAY[26/12/2016, 27/12/2016, 28/12/2016, 29/12/2016]
传入的价值 [27/12/2016]
上面可能是个简单的错误!所以对此有任何帮助.也会有时间影响被检查的日期?
您可以尝试使用该find()方法(如果支持ecmascript):
var array = ["26/12/2016", "27/12/2016", "28/12/2016", "29/12/2016"];
var value1 = "26/12/2016"; //exists
var value2 = "26/12/2026"; //doesn't exist
function isInArray(array, value) {
return (array.find(item => {return item == value}) || []).length > 0;
}
console.log(isInArray(array, value1));
console.log(isInArray(array, value2));Run Code Online (Sandbox Code Playgroud)
var array = [new Date("December 26, 2016 00:00:00"), new Date("December 27, 2016 00:00:00"), new Date("December 28, 2016 00:00:00"), new Date("December 29, 2016 00:00:00")];
var value1 = new Date("December 26, 2016 00:00:00"); //exists
var value2 = new Date("December 16, 2026 00:00:00"); //doesn't exist
function isInArray(array, value) {
return !!array.find(item => {return item.getTime() == value.getTime()});
}
console.log(isInArray(array, value1));
console.log(isInArray(array, value2));Run Code Online (Sandbox Code Playgroud)
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