Had*_*oke 4 python multithreading deadlock multiprocessing
上下文
我需要在multiprocessing.ThreadPool中运行multiprocessing.Process.起初看起来很奇怪,但这是我发现处理segfault的唯一方法,因为我使用的是c ++共享库.如果追加了段错误,则该进程被终止,我可以检查process.exitcode并处理它.
问题
过了一会儿,当我试图加入这个过程时会出现死锁.
这是我的代码的简单版本:
import sys, time, multiprocessing
from multiprocessing.pool import ThreadPool
def main():
# Launch 8 workers
pool = ThreadPool(8)
it = pool.imap(run, range(500))
while True:
try:
it.next()
except StopIteration:
break
def run(value):
# Each worker launch it own Process
process = multiprocessing.Process(target=run_and_might_segfault, args=(value,))
process.start()
while process.is_alive():
sys.stdout.write('.')
sys.stdout.flush()
time.sleep(0.1)
# Will never join after a while, because of a mystery deadlock
process.join()
# Deals with process.exitcode to log errors
def run_and_might_segfault(value):
# Load a shared library and do stuff (could throw c++ exception, segfault ...)
print(value)
if __name__ == '__main__':
main()
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这是一个可能的输出:
? ~ python m.py
..0
1
........8
.9
.......10
......11
........12
13
........14
........16
........................................................................................
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正如您所看到的,process.is_alive()在几次迭代之后总是如此,该过程永远不会加入.
如果我按CTRL-C脚本获取此堆栈跟踪:
Traceback (most recent call last):
File "/usr/local/Cellar/python3/3.5.1/Frameworks/Python.framework/Versions/3.5/lib/python3.5/multiprocessing/pool.py", line 680, in next
item = self._items.popleft()
IndexError: pop from an empty deque
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "m.py", line 30, in <module>
main()
File "m.py", line 9, in main
it.next()
File "/usr/local/Cellar/python3/3.5.1/Frameworks/Python.framework/Versions/3.5 /lib/python3.5/multiprocessing/pool.py", line 684, in next
self._cond.wait(timeout)
File "/usr/local/Cellar/python3/3.5.1/Frameworks/Python.framework/Versions/3.5 /lib/python3.5/threading.py", line 293, in wait
waiter.acquire()
KeyboardInterrupt
Error in atexit._run_exitfuncs:
Traceback (most recent call last):
File "/usr/local/Cellar/python3/3.5.1/Frameworks/Python.framework/Versions/3.5 /lib/python3.5/multiprocessing/popen_fork.py", line 29, in poll
pid, sts = os.waitpid(self.pid, flag)
KeyboardInterrupt
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PS 在macos上使用python 3.5.2.
各种帮助都很感激,谢谢.
编辑
我尝试使用python 2.7,它运行良好.可能只是一个python 3.5问题?
小智 6
这个问题也在CPython的最新版本中重现 - Python 3.7.0a0 (default:4e2cce65e522, Oct 13 2016, 21:55:44).
如果你使用gdb 附加到其中一个卡住的进程,你会发现它正在尝试获取一个锁定的sys.stdout.flush()调用:
(gdb) py-list
263 import traceback
264 sys.stderr.write('Process %s:\n' % self.name)
265 traceback.print_exc()
266 finally:
267 util.info('process exiting with exitcode %d' % exitcode)
>268 sys.stdout.flush()
269 sys.stderr.flush()
270
271 return exitcode
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Python级别的回溯看起来像这样:
(gdb) py-bt
Traceback (most recent call first):
File "/home/rpodolyaka/src/cpython/Lib/multiprocessing/process.py", line 268, in _bootstrap
sys.stdout.flush()
File "/home/rpodolyaka/src/cpython/Lib/multiprocessing/popen_fork.py", line 74, in _launch
code = process_obj._bootstrap()
File "/home/rpodolyaka/src/cpython/Lib/multiprocessing/popen_fork.py", line 20, in __init__
self._launch(process_obj)
File "/home/rpodolyaka/src/cpython/Lib/multiprocessing/context.py", line 277, in _Popen
return Popen(process_obj)
File "/home/rpodolyaka/src/cpython/Lib/multiprocessing/context.py", line 223, in _Popen
return _default_context.get_context().Process._Popen(process_obj)
File "/home/rpodolyaka/src/cpython/Lib/multiprocessing/process.py", line 105, in start
self._popen = self._Popen(self)
File "deadlock.py", line 17, in run
process.start()
File "/home/rpodolyaka/src/cpython/Lib/multiprocessing/pool.py", line 119, in worker
result = (True, func(*args, **kwds))
File "/home/rpodolyaka/src/cpython/Lib/threading.py", line 864, in run
self._target(*self._args, **self._kwargs)
File "/home/rpodolyaka/src/cpython/Lib/threading.py", line 916, in _bootstrap_inner
self.run()
File "/home/rpodolyaka/src/cpython/Lib/threading.py", line 884, in _bootstrap
self._bootstrap_inner()
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在解释器级别,它看起来像:
(gdb) frame 6
(gdb) list
287 return 0;
288 }
289 relax_locking = (_Py_Finalizing != NULL);
290 Py_BEGIN_ALLOW_THREADS
291 if (!relax_locking)
292 st = PyThread_acquire_lock(self->lock, 1);
293 else {
294 /* When finalizing, we don't want a deadlock to happen with daemon
295 * threads abruptly shut down while they owned the lock.
296 * Therefore, only wait for a grace period (1 s.). ... */
(gdb) p /x self->lock
$1 = 0xd25ce0
(gdb) p /x self->owner
$2 = 0x7f9bb2128700
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注意,从这个特定子进程的角度来看,锁仍然由父进程(LWP 1105)中的一个线程拥有:
(gdb) info threads
Id Target Id Frame
* 1 Thread 0x7f9bb5559440 (LWP 1102) "python" 0x00007f9bb5157577 in futex_abstimed_wait_cancelable (private=0, abstime=0x0, expected=0,
futex_word=0xe4d340) at ../sysdeps/unix/sysv/linux/futex-internal.h:205
2 Thread 0x7f9bb312a700 (LWP 1103) "python" 0x00007f9bb4780253 in select () at ../sysdeps/unix/syscall-template.S:84
3 Thread 0x7f9bb2929700 (LWP 1104) "python" 0x00007f9bb4780253 in select () at ../sysdeps/unix/syscall-template.S:84
4 Thread 0x7f9bb2128700 (LWP 1105) "python" 0x00007f9bb4780253 in select () at ../sysdeps/unix/syscall-template.S:84
5 Thread 0x7f9bb1927700 (LWP 1106) "python" 0x00007f9bb4780253 in select () at ../sysdeps/unix/syscall-template.S:84
6 Thread 0x7f9bb1126700 (LWP 1107) "python" 0x00007f9bb4780253 in select () at ../sysdeps/unix/syscall-template.S:84
7 Thread 0x7f9bb0925700 (LWP 1108) "python" 0x00007f9bb4780253 in select () at ../sysdeps/unix/syscall-template.S:84
8 Thread 0x7f9b9bfff700 (LWP 1109) "python" 0x00007f9bb4780253 in select () at ../sysdeps/unix/syscall-template.S:84
9 Thread 0x7f9b9b7fe700 (LWP 1110) "python" 0x00007f9bb4780253 in select () at ../sysdeps/unix/syscall-template.S:84
10 Thread 0x7f9b9affd700 (LWP 1111) "python" 0x00007f9bb4780253 in select () at ../sysdeps/unix/syscall-template.S:84
11 Thread 0x7f9b9a7fc700 (LWP 1112) "python" 0x00007f9bb5157577 in futex_abstimed_wait_cancelable (private=0, abstime=0x0, expected=0,
futex_word=0x7f9b80001ed0) at ../sysdeps/unix/sysv/linux/futex-internal.h:205
12 Thread 0x7f9b99ffb700 (LWP 1113) "python" 0x00007f9bb5157577 in futex_abstimed_wait_cancelable (private=0, abstime=0x0, expected=0,
futex_word=0x7f9b84001bb0) at ../sysdeps/unix/sysv/linux/futex-internal.h:205
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所以它确实是一个死锁,它发生的原因是你sys.stdout在原始进程中同时在多个线程中执行写入和刷新,同时还创建了子进程 - 由于fork(2)系统调用的性质,子进程继承了父内存,包括获取的锁:fork()调用必须有在获取锁定时执行,即使父进程最终释放它,子进程也不会看到,因为每个进程都有自己的内存空间,这是在写入时复制的.
因此,在将多线程与多处理混合时需要非常小心,并且fork()如果要在子进程中使用它们,请确保之前正确释放所有锁.
它与http://bugs.python.org/issue6721中描述的非常相似
请注意,如果您sys.stdout从代码段中删除了相互作用,它将正常运行.