在后台 swift 3 中播放视频

abd*_*man 2 ios swift3

你好,我正在尝试在后台播放视频,但它给出了一个错误,错误是“在解包可选值时意外发现 nil”,我已经在 Bundle 中设置了视频,并在需要时选择复制

这是我的代码

import UIKit
import AVFoundation

class ViewController: UIViewController {

    var avPlayer: AVPlayer!
    var avPlayerLayer: AVPlayerLayer!
    var paused: Bool = false

    override func viewDidLoad() {
        super.viewDidLoad()

        let url = Bundle.main.url(forResource: "Grad_Cap_Toss", withExtension: "mp4")


        avPlayer = AVPlayer(url: url!)
        avPlayerLayer = AVPlayerLayer(player: avPlayer)
        avPlayerLayer.videoGravity = AVLayerVideoGravityResizeAspectFill
        avPlayer.volume = 0
        avPlayer.actionAtItemEnd = AVPlayerActionAtItemEnd.none

        avPlayerLayer.frame = view.layer.bounds
        view.backgroundColor = UIColor.clear;
        view.layer.insertSublayer(avPlayerLayer, at: 0)

        NotificationCenter.default.addObserver(self,selector: Selector(("playerItemDidReachEnd:")),name: NSNotification.Name.AVPlayerItemDidPlayToEndTime,object: avPlayer.currentItem)

    }
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请任何机构对此有想法,谢谢

tBu*_*Bug 6

  1. 首先,将视频文件拖放到您的项目中。
    1. 然后导入AVFundation。
    2. 添加示例:var player: AVPlayer?
    3. @IBOutlet 弱变量 videoView:UIView!- 将故事板的视图连接到您的 VC 课程。
    4. 之后,您将此代码粘贴到您的 ViewController 中。
    5. 在您的 viewDidLoad() 中调用“playBackgoundVideo()”
private func playBackgoundVideo() {
    if let filePath = Bundle.main.path(forResource: "your_video_here", ofType:"mp4") {
        let filePathUrl = NSURL.fileURL(withPath: filePath)
        player = AVPlayer(url: filePathUrl)
        let playerLayer = AVPlayerLayer(player: player)
        playerLayer.frame = self.videoView.bounds
        playerLayer.videoGravity = AVLayerVideoGravityResizeAspectFill
        NotificationCenter.default.addObserver(forName: .AVPlayerItemDidPlayToEndTime, object: self.player?.currentItem, queue: nil) { (_) in
            self.player?.seek(to: kCMTimeZero)
            self.player?.play()
        }
        self.videoView.layer.addSublayer(playerLayer)
        player?.play()
    }
}
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这是 swift 4.0 它有效^__^