操纵包含数字的字符串列表以输出数字列表

Question

我在操作字符串列表时寻求帮助,我想要提取数字,例如:

 x = ['aa bb qq 2 months  60%', 'aa bb qq 3 months  70%', 'aa bb qq 1 month  80%']

我想到:

[[2.0,60.0],[3.0,70.0],[1.0,80.0]]

以优雅的方式.

第一个数字应始终为整数,但第二个数字可以是带小数值的float

我的肮脏工作是这样的:

x_split = [y.replace("%", "").split() for y in x]
x_float = [[float(s) for s in x if s.isdigit()] for x in x_split]

Out[100]: [[2.0, 60.0], [3.0, 70.0], [1.0, 80.0]]

Answer 1

使用正则表达式匹配整数和浮点数.

import re
[[float(n) for n in re.findall(r'\d+\.?\d*', s)] for s in x]

正则表达式(r'\d+\.?\d*')的解释:

r    #  a raw string so that back slashes are not converted  
\d   #  digit 0 to 9
+    #  one or more of the previous pattern (\d)
\.   #  a decimal point
?    #  zero or one of the previous pattern (\.)
\d   #  digit 0 to 9
*    #  zero or more of the previous pattern (\d)