如何在JPA中使用Postgres JSONB数据类型?

jus*_*ode 20 java postgresql json jpa eclipselink

我没有找到使用JPA(EclipseLink)从PostgreSQL映射JSON和JSONB数据类型的方法.是否有人使用JPA的这种数据类型,可以给我一些有用的例子吗?

jus*_*ode 24

所有的答案都帮助我达到了为JPA做好准备的最终解决方案,而不是EclipseLink或Hibernate.

import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.ObjectMapper;
import java.io.IOException;
import javax.json.Json;
import javax.json.JsonObject;
import javax.persistence.Converter;
import org.postgresql.util.PGobject;

@Converter(autoApply = true)
public class JsonConverter implements javax.persistence.AttributeConverter<JsonObject, Object> {

  private static final long serialVersionUID = 1L;
  private static ObjectMapper mapper = new ObjectMapper();

  @Override
  public Object convertToDatabaseColumn(JsonObject objectValue) {
    try {
      PGobject out = new PGobject();
      out.setType("json");
      out.setValue(objectValue.toString());
      return out;
    } catch (Exception e) {
      throw new IllegalArgumentException("Unable to serialize to json field ", e);
    }
  }

  @Override
  public JsonObject convertToEntityAttribute(Object dataValue) {
    try {
      if (dataValue instanceof PGobject && ((PGobject) dataValue).getType().equals("json")) {
        return mapper.reader(new TypeReference<JsonObject>() {
        }).readValue(((PGobject) dataValue).getValue());
      }
      return Json.createObjectBuilder().build();
    } catch (IOException e) {
      throw new IllegalArgumentException("Unable to deserialize to json field ", e);
    }
  }
}
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  • 此解决方案不适用于Hibernate(当前5.2.10.Final).错误是`org.hibernate.MappingException:没有JDBC类型的Dialect映射:SOME_RANDOM_NUMBER`,显然开发人员不会修复它.他们提出的解决方案是使用Generic Hibernate Types(重要的东西)https://vladmihalcea.com/2016/06/20/how-to-map-json-objects-using-generic-hibernate-types/ (9认同)
  • 我已经为Hibernate尝试了类似的东西,但似乎`AttributeConverter`最终以`Object`被`Hibernate`打破了.我只是得到一个错误,说"未知的jdbc类型"或类似的东西.真的很遗憾,因为这种方法更漂亮,锅炉板更少. (4认同)
  • 由于不建议使用mapper.read,因此必须将mapper.read替换为mapper.readFor。 (3认同)

Tob*_*obb 5

编辑:我现在看到这非常Hibernate依赖.但也许你可以找到类似的东西EclipseLink..

我只是添加我的答案,它来自另一个SO答案,但无论如何......这将映射jsonb到JsonObjectGoogle gson,但如果需要,您可以将其更改为其他内容.要改变别的东西,改变nullSafeGet,nullSafeSet和deepCopy方法.

public class JsonbType implements UserType {

    @Override
    public int[] sqlTypes() {
        return new int[] { Types.JAVA_OBJECT };
    }

    @Override
    public Class<JsonObject> returnedClass() {
        return JsonObject.class;
    }

    @Override
    public boolean equals(final Object x, final Object y) {
        if (x == y) {
            return true;
        }
        if (x == null || y == null) {
            return false;
        }
        return x.equals(y);
    }

    @Override
    public int hashCode(final Object x) {
        if (x == null) {
            return 0;
        }

        return x.hashCode();
    }

    @Nullable
    @Override
    public Object nullSafeGet(final ResultSet rs,
                              final String[] names,
                              final SessionImplementor session,
                              final Object owner) throws SQLException {
        final String json = rs.getString(names[0]);
        if (json == null) {
            return null;
        }

        final JsonParser jsonParser = new JsonParser();
        return jsonParser.parse(json).getAsJsonObject();
    }

    @Override
    public void nullSafeSet(final PreparedStatement st,
                            final Object value,
                            final int index,
                            final SessionImplementor session) throws SQLException {
        if (value == null) {
            st.setNull(index, Types.OTHER);
            return;
        }

        st.setObject(index, value.toString(), Types.OTHER);
    }

    @Nullable
    @Override
    public Object deepCopy(@Nullable final Object value) {
        if (value == null) {
            return null;
        }
        final JsonParser jsonParser = new JsonParser();
        return jsonParser.parse(value.toString()).getAsJsonObject();
    }

    @Override
    public boolean isMutable() {
        return true;
    }

    @Override
    public Serializable disassemble(final Object value) {
        final Object deepCopy = deepCopy(value);

        if (!(deepCopy instanceof Serializable)) {
            throw new SerializationException(
                    String.format("deepCopy of %s is not serializable", value), null);
        }

        return (Serializable) deepCopy;
    }

    @Nullable
    @Override
    public Object assemble(final Serializable cached, final Object owner) {
        return deepCopy(cached);
    }

    @Nullable
    @Override
    public Object replace(final Object original, final Object target, final Object owner) {
        return deepCopy(original);
    }
}
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要使用它,请执行:

public class SomeEntity {

    @Column(name = "jsonobject")
    @Type(type = "com.myapp.JsonbType") 
    private JsonObject jsonObject;
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此外,您需要设置您的方言以指示JAVA_OBJECT= jsonb:

registerColumnType(Types.JAVA_OBJECT, "jsonb");
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