sequelize 从 .then 返回结果

Question

我有以下代码：

var ORM = require('../helpers/mysql_orm');
var log = require('../helpers/logger');  

function UserModel() {

   this.User = ORM.define('User', {

        }, {
        tableName: 'User',
        timestamps: false,
        }); 
}


UserModel.prototype.findOneByCredinitals = function (creditinals) {

    this.User.findOne({ 
            attributes:['username','id'],
            where: 
             { 
              username:creditinals.principal,
              password:creditinals.creditinal}
            })
            .then(function(user) {
           console.log("inside then function"+user);
            return user;
    })
   // console.log(result);

},
UserModel.prototype.findAllByLimit = function(req,res) {


}


module.exports= new UserModel;

//app.js

var result = User.findOneByCredinitals({principal: 'admin',creditinal:'danieladenew'});

console.log("returned "+result);

这是 app.js 的结果

------------------------------------------------
returned undefined
inside then function User Sequelize Instance i.e Useriffound and displayed.

我如何将用户对象从那时返回到 app.js 代码？

Answer 1

您需要返回承诺才能显示数据。

UserModel.prototype.findOneByCredential = function (credentials) {

    return this.User.findOne({ 
        attributes: ['username', 'id'],
        where: { 
            username: credential.principal,
            password: credential.credential
        }
    }).then(function(user) {
            console.log("inside then function"+user);
            return user;
        }
    });
},

另外，添加一个catch块可能是个好主意。如果查询失败，你将不知道其他情况