我正在尝试快速执行以下操作-尝试反向解码数组中的地址列表并打印其纬度/经度坐标。我的代码如下。
let addressArray = ["Address 1", "Address 2"]
var coordinatesArray = [CLLocationCoordinate2D]()
override func viewDidLoad() {
super.viewDidLoad()
createAddressList()
printAddressList()
}
func printAddressList() {
for i in 0 ..< addressArray.count {
print("Address = \(addressArray[i]) Coordinates = \(coordinatesArray[i].latitude),\(coordinatesArray[i].latitude)")
}
func createAddressList() {
for i in 0 ..< addressArray.count {
let address = addressArray[i]
geocoder.geocodeAddressString(address, completionHandler: {(placemarks, error) -> Void in
print("Address = \(address)");
if let placemark = placemarks?.first {
let coordinate = placemark.location?.coordinate
self.coordinatesArray.append(coordinate!)
}
})
}
}
}
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该代码仅显示已解码的第一个地址,然后没有任何反应。
我确实有如下修复方法,如下所示,它是将printAddressList调用从viewDidLoad方法中移出,如下所示
func createAddressList() {
if count < self.addressArray.count {
let address = addressArray[count]
geocoder.geocodeAddressString(address, completionHandler: {(placemarks, error) -> Void in
print("Address = \(address)");
if let placemark = placemarks?.first {
let coordinate = placemark.location?.coordinate
self.coordinatesArray.append(coordinate!)
}
print("Count = \(self.count)")
self.count += 1
self.createAddressList()
})
} else {
printAddressList()
}
}
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尽管后一种解决方案可行,但我发现它并不干净,我想知道在使代码可读和干净的同时执行此操作的正确方法。
如何使用这种结构?
let workGroup = dispatch_group_create()
for i in 0..<addressArray.count {
dispatch_group_enter(workGroup)
performGeoCoding({ successCallback :
dispatch_group_leave(workGroup)
})
}
dispatch_group_notify(workGroup, dispatch_get_main_queue()){
successCallback()
printAddressList()
}
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有一个关于dispatch_group很不错的教程在这里。