如何使logging.logger表现得像print

Question

假设我有这个logging.logger实例:

import logging
logger = logging.getLogger('root')
FORMAT = "[%(filename)s:%(lineno)s - %(funcName)20s() ] %(message)s"
logging.basicConfig(format=FORMAT)
logger.setLevel(logging.DEBUG)

当我尝试使用它时,就像带有动态数量参数的内置打印一样:

>>> logger.__class__
<class 'logging.Logger'>
>>> logger.debug("hello")
[<stdin>:1 -             <module>() ] hello
>>> logger.debug("hello","world")
Traceback (most recent call last):
  File "c:\Python2711\Lib\logging\__init__.py", line 853, in emit
    msg = self.format(record)
  File "c:\Python2711\Lib\logging\__init__.py", line 726, in format
    return fmt.format(record)
  File "c:\Python2711\Lib\logging\__init__.py", line 465, in format
    record.message = record.getMessage()
  File "c:\Python2711\Lib\logging\__init__.py", line 329, in getMessage
    msg = msg % self.args
TypeError: not all arguments converted during string formatting
Logged from file <stdin>, line 1

我怎样才能使用logging.Logger来模拟打印行为？

Answer 1

或者，定义一个接受的函数*args，然后join在调用中接受它们logger：

def log(*args, logtype='debug', sep=' '):
    getattr(logger, logtype)(sep.join(str(a) for a in args))

为了灵活性，我logtype在这里添加了一个，但如果不需要，您可以将其删除。