用胡子迭代数组

Question

如何获取迭代中当前元素的引用？

{{#my_array}}
    <p>{{__what_goes_here?__}}</p>
{{/my_array}}

我希望我只是忽略了显而易见的事实.

Answer 1

根据spec的changelog,隐式迭代器(.)在规范的v1.1.0中添加.每个实现至少v1.1.0的Mustache库都应该支持这个.

{{#array_of_strings}}<li>{{.}}</li>{{/array_of_strings}}

Answer 2

来自源代码https://github.com/bobthecow/mustache.php

/**
 * The {{%IMPLICIT-ITERATOR}} pragma allows access to non-associative array data in an
 * iterable section:
 *
 *     $context = array('items' => array('foo', 'bar', 'baz'));
 *
 * With this template:
 *
 *     {{%IMPLICIT-ITERATOR}}{{#items}}{{.}}{{/items}}
 *
 * Would render as `foobarbaz`.
 *
 * {{%IMPLICIT-ITERATOR}} accepts an optional 'iterator' argument which allows implicit
 * iterator tags other than {{.}} ...
 *
 *     {{%IMPLICIT-ITERATOR iterator=i}}{{#items}}{{i}}{{/items}}
 */

Answer 3

我离开了我的代码一段时间,并记得Ruby是鸭子类型.由于我的数组是字符串,我所需要的只是:

{{#my_array}}
    <p>{{to_s}}</p>
{{/my_array}}

我会在这里留下这个问题,希望能在某些时候拯救别人.