Mockito:如何验证一个方法只调用一次精确参数忽略对其他方法的调用？

Question

在Java中使用Mockito如何验证方法只调用一次精确参数忽略对其他方法的调用？

示例代码:

public class MockitoTest {

    interface Foo {
        void add(String str);
        void clear();
    }


    @Test
    public void testAddWasCalledOnceWith1IgnoringAllOtherInvocations() throws Exception {
        // given
        Foo foo = Mockito.mock(Foo.class);

        // when
        foo.add("1"); // call to verify
        foo.add("2"); // !!! don't allow any other calls to add()
        foo.clear();  // calls to other methods should be ignored

        // then
        Mockito.verify(foo, Mockito.times(1)).add("1");
        // TODO: don't allow all other invocations with add() 
        //       but ignore all other calls (i.e. the call to clear())
    }

}

该TODO: don't allow all other invocations with add()部分应该做些什么？

尝试失败:

1. verifyNoMoreInteractions(foo);

不.它不允许调用其他方法,如clear().

2. verify(foo, times(0)).add(any());

不.它没有考虑到我们允许一个电话add("1").

Answer 1

Mockito.verify(foo, Mockito.times(1)).add("1");
Mockito.verify(foo, Mockito.times(1)).add(Mockito.anyString());

第一个verify检查预期的参数化调用,第二个verify检查只有一个调用add.

Answer 2

The previous answer can be simplified even further.

Mockito.verify(foo).add("1");
Mockito.verify(foo).add(Mockito.anyString());

The single parameter verify method is just an alias to the times(1)implementation.