烧瓶socketio向特定用户发出

Question

我看到有关于此主题的问题,但具体代码未概述.假设我只想向第一个客户端发射.

例如(在events.py中):

clients = []

@socketio.on('joined', namespace='/chat')
def joined(message):
    """Sent by clients when they enter a room.
    A status message is broadcast to all people in the room."""
    #Add client to client list
    clients.append([session.get('name'), request.namespace])
    room = session.get('room')
    join_room(room)
    emit('status', {'msg': session.get('name') + ' has entered the room.'}, room=room)
    #I want to do something like this, emit message to the first client
    clients[0].emit('status', {'msg': session.get('name') + ' has entered the room.'}, room=room)

这怎么做得好？

谢谢

Answer 1

我不确定我理解向第一个客户端发送的逻辑,但无论如何,这是如何做到的:

clients = []

@socketio.on('joined', namespace='/chat')
def joined(message):
    """Sent by clients when they enter a room.
    A status message is broadcast to all people in the room."""
    # Add client to client list
    clients.append(request.sid)

    room = session.get('room')
    join_room(room)

    # emit to the first client that joined the room
    emit('status', {'msg': session.get('name') + ' has entered the room.'}, room=clients[0])

如您所见,每个客户都有自己的空间.该会议室的名称是Socket.IO会话ID,您可以request.sid从该客户端处理事件时获取该ID .因此,您需要做的就是sid为所有客户端存储此值,然后在emit调用中使用所需的一个作为房间名称.