触发Maven远程释放

Question

我想以编程方式从Java程序启动Maven版本.该网页显示了一般如何完成.这就是我做的:

    final URL url = new URL("http://jenkins/job/MyProject/m2release/submit");

    final HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
    urlConnection.setRequestMethod("POST"); 
    urlConnection.setDoOutput(true);

    final String userpass = "User:Password";
    final String authentication = "Basic " + DatatypeConverter.printBase64Binary(userpass.getBytes());
    urlConnection.setRequestProperty("Authorization", authentication);

    try (final OutputStream os = urlConnection.getOutputStream();
            final BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(os, "UTF-8"));) {
        writer.write("releaseVersion=1.2.3&");
        writer.write("developmentVersion=1.2.4-SNAPSHOT&");
        // writer.write("isDryRun=on&"); // uncomment for dry run
        writer.write("scmUsername=User&");
        writer.write("scmPassword=Password&");
        writer.write("scmCommentPrefix=[test]&");
        writer.write("json={\"releaseVersion\":\"1.2.3\",\"developmentVersion\":\"1.2.4-SNAPSHOT\",\"isDryRun\":false}&");
        writer.write("Submit=Schedule Maven Release Build");

        writer.flush();
    }

    urlConnection.connect();

    try (BufferedReader reader = new BufferedReader(
            new InputStreamReader(urlConnection.getInputStream(), "UTF-8"))) {
        for (String line; (line = reader.readLine()) != null;) {
            System.out.println(line);
        }
    }

这个论坛建议"只要看看你发布的表格,你应该能够制作一个cURL请求",这就是我做到这一点的目的.该发布至少开始.

我现在不知道如何逃避一切.浏览器将空格显示为"+",但如果我以这种方式发送数据则不起作用.事实上,"+","+"和"%20"都不是一个空间.

我仍然进入Unable to commit files构建,所以我很确定用户名/密码/注释前缀有问题.即使登录已发送,Jenkins本身也会返回登录页面("需要身份验证").

在Jenkins上触发Maven发布的正确方法是什么？

Answer 1

好的，我的旧方法中缺少的参数是：

writer.write("specifyScmCredentials=on&");
writer.write("specifyScmCommentPrefix=on&");