Powershell返回错误的结果

Question

我在Powershell中遇到了这个奇怪的问题(不是在其他语言中).有人可以向我解释为什么会这样吗？

我试图返回一个指定的数字(数字8),但该函数不断向我抛出一切.这是一个错误还是设计？

Function GetNum() {
   Return 10
}

Function Main() {

    $Number10 = GetNum
    $number10 #1 WHY NO OUTPUT HERE ??????? I don't want to use write host
    $result = 8  # I WANT THIS NUMBER ONLY
    PAUSE
    return $result
}

do {    
    $again = Main
    Write-Host "RESULT IS "$again # Weird Result, I only want Number 8
} While ($again -eq 10) # As the result is wrong, it loops forever

Answer 1

这是一个错误还是设计？

按设计.在PowerShell中,cmdlet可以返回对象流,就像yield return在C#中使用以返回IEnumerable集合一样.

该return不需要的关键字为要返回的输出值,它简单地退出(或从返回)当前范围.

从Get-Help about_Return(重点补充):

    The Return keyword exits a function, script, or script block. It can be
    used to exit a scope at a specific point, to return a value, or to indicate
    that the end of the scope has been reached.


    Users who are familiar with languages like C or C# might want to use the
    Return keyword to make the logic of leaving a scope explicit.


    In Windows PowerShell, the results of each statement are returned as
    output, even without a statement that contains the Return keyword.
    Languages like C or C# return only the value or values that are specified
    by the Return keyword.