Powershell Array用逗号分隔字符串

Question

我有一个数组,我需要输出到逗号分隔的字符串,但我还需要引号"".这就是我所拥有的.

$myArray = "file1.csv","file2.csv"
$a = ($myArray -join ",")
$a

结果输出 $a 结束

file1.csv,file2.csv

我想要的输出是

"file1.csv","file2.csv"

我怎么能做到这一点？

Answer 1

干得好:

[array]$myArray = '"file1.csv"','"file2.csv"'
[string]$a = $null

$a = $myArray -join ","

$a

输出:

"file1.csv","file2.csv"

你只需要有办法逃脱".所以,你可以通过绕过它来做到这一点'.

Answer 2

我知道这个线程已经老了,但这里有其他解决方案

$myArray = "file1.csv","file2.csv"

# Solution with single quote
$a = "'$($myArray -join "','")'"
$a
# Result = 'file1.csv','file2.csv'

# Solution with double quotes
$b = '"{0}"' -f ($myArray -join '","')
$b
# Result = "file1.csv","file2.csv"

Answer 3

如果使用 PowerShell Core（当前为 7.1），则可以使用Join-String
这在 PowerShell 5.1 中不可用

$myArray | Join-String -DoubleQuote -Separator ','

输出：

"file1.csv","file2.csv"