我正在尝试在HList上添加约束(来自Shapeless):
TA(从0到N);TB.我的示例有这种类型层次结构:
trait T
case class TA extends T
case class TB extends T
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举个例子:
tb :: HNil 已验证ta :: tb ::HNil 已验证ta :: tb :: ta :: HNil 已验证ta :: HNil 是无效的HNil 是无效的我无法弄清楚如何将其表达为约束.
您可以使用自定义类型类来执行此操作,该类可以确定其中只有一个TB元素和所有其他元素TA.如果你想象归纳地建立这个列表,你会发现有两种情况你需要处理 - 你到目前为止所看到的一切都是TA(我们可以用a见证ToList[T, TA])并且当前元素是a TB,或者你'已经看过单个TB,当前元素是TA:
import shapeless._, ops.hlist.{ ToList }
trait T
case class TA() extends T
case class TB() extends T
trait UniqueTB[L <: HList] extends DepFn1[L] {
type Out = TB
def apply(l: L): TB
}
object UniqueTB {
def apply[L <: HList](implicit utb: UniqueTB[L]): UniqueTB[L] = utb
def getTB[L <: HList](l: L)(implicit utb: UniqueTB[L]): TB = utb(l)
implicit def firstTB[T <: HList](
implicit tl: ToList[T, TA]
): UniqueTB[TB :: T] = new UniqueTB[TB :: T] {
def apply(l: TB :: T): TB = l.head
}
implicit def afterTB[T <: HList](
implicit utb: UniqueTB[T]
): UniqueTB[TA :: T] = new UniqueTB[TA :: T] {
def apply(l: TA :: T): TB = utb(l.tail)
}
}
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然后:
scala> UniqueTB[TB :: HNil]
res0: UniqueTB[shapeless.::[TB,shapeless.HNil]] = UniqueTB$$anon$1@385c6929
scala> UniqueTB[TA :: TB :: HNil]
res1: UniqueTB[shapeless.::[TA,shapeless.::[TB,shapeless.HNil]]] = UniqueTB$$anon$2@682dd97e
scala> UniqueTB[TA :: TB :: TA :: HNil]
res2: UniqueTB[shapeless.::[TA,shapeless.::[TB,shapeless.::[TA,shapeless.HNil]]]] = UniqueTB$$anon$2@5ef48f82
scala> UniqueTB[TB :: HNil]
res3: UniqueTB[shapeless.::[TB,shapeless.HNil]] = UniqueTB$$anon$1@33be241
scala> UniqueTB[TA :: HNil]
<console>:25: error: could not find implicit value for parameter utb: UniqueTB[shapeless.::[TA,shapeless.HNil]]
UniqueTB[TA :: HNil]
^
scala> UniqueTB[HNil]
<console>:25: error: could not find implicit value for parameter utb: UniqueTB[shapeless.HNil]
UniqueTB[HNil]
^
scala> UniqueTB[TB :: TB :: HNil]
<console>:25: error: could not find implicit value for parameter utb: UniqueTB[shapeless.::[TB,shapeless.::[TB,shapeless.HNil]]]
UniqueTB[TB :: TB :: HNil]
^
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我已经为类型类提供了一个返回的操作TB,但是如果你不需要它,你可以将它保留为无方法.