spa*_*row 10 python csv dataframe pandas python-requests
使用请求我正在创建一个.csv格式的对象.然后我怎么能用pandas将该对象写入DataFrame?
以文本格式获取请求对象:
import requests
import pandas as pd
url = r'http://test.url'
r = requests.get(url)
r.text #this will return the data as text in csv format
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我试过(不起作用):
pd.read_csv(r.text)
pd.DataFrame.from_csv(r.text)
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Mer*_*lin 20
试试这个
import requests
import pandas as pd
import io
urlData = requests.get(url).content
rawData = pd.read_csv(io.StringIO(urlData.decode('utf-8')))
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我想你可以用read_csv用url:
pd.read_csv(url)
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filepath_or_buffer:str,pathlib.Path,py._path.local.LocalPath或任何带有read()方法的对象(例如文件句柄或StringIO)
字符串可以是URL.有效的URL方案包括http,ftp,s3和file.对于文件URL,需要主机.例如,本地文件可以是file://localhost/path/to/table.csv
如果它不起作用,请尝试:
import pandas as pd
import io
import requests
url = r'http://...'
r = requests.get(url)
df = pd.read_csv(io.StringIO(r)
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使用“read_csv with url”有效:
import requests, csv
import pandas as pd
url = 'https://arte.folha.uol.com.br/ciencia/2020/coronavirus/csv/mundo/dados-bra.csv'
corona_bra = pd.read_csv(url)
print(corona_bra.head())
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