Bash参数替换条带#cirst

Question

有没有简单的方法#从参数替换的bash变量中剥离/替换第一次出现的字符？我尝试了以下但它不起作用:

$ VERSION=0.11.3-issue#18.6a0b43d.123
$ echo ${VERSION#'#'}
$ echo ${VERSION#\#}

我希望我的输出是:

0.11.3-issue18.6a0b43d.123
#           ^
#           no #

对此有什么简单的解决方案 也许是以完全不同的方式？

Answer 1

如果您只想"删除"第一次出现#,请使用${parameter/pattern}.

${parameter/pattern/string}
       Pattern substitution.  The pattern is expanded to produce a pat-
       tern just as in pathname expansion.  Parameter is  expanded  and
       the  longest match of pattern against its value is replaced with
       string.  If pattern begins with /, all matches  of  pattern  are
       replaced   with  string.   Normally  only  the  first  match  is
       replaced.  If pattern begins with #, it must match at the begin-
       ning of the expanded value of parameter.

• 匹配是使用路径名扩展(思考?和*)完成的.
• 此外#,在模式的开头有一个特殊的含义,这就是我们用它替换它的原因\.然后序列\#匹配文字#而没有#模式开头的特殊含义.

例

VERSION=0.11.3-issue#18.6a0b43d.123
echo ${VERSION/\#/}

产量

0.11.3-issue18.6a0b43d.123