'Promise <void>'类型中不存在属性'catch'

Question

我正在使用Mongoose和Bluebird的打字稿.Mongoose设置为返回Bluebird承诺,但我不知道如何"告诉"TypeScript.

例如Message,如果我尝试执行以下操作,我有一个Mongoose模型:

new Message(messageContent)
  .save()
  .then(() => {...})
  .catch(next);

TypeScript抱怨Property 'catch' does not exist on type 'Promise<void>'.因为它认为.save()(或任何其他Mongoose方法返回Promise)返回一个'常规'Promise(实际上没有.catch()方法)而不是Bluebird promise.

如何更改Mongoose方法的返回类型,以便TypeScript知道它返回了Bluebird的承诺？

Answer 1

根据DefinitelyTyped 的 mongoose.d.ts

/**
 * To assign your own promise library:
 *
 * 1. Include this somewhere in your code:
 *    mongoose.Promise = YOUR_PROMISE;
 *
 * 2. Include this somewhere in your main .d.ts file:
 *    type MongoosePromise<T> = YOUR_PROMISE<T>;
 */

因此，您的主 .d.ts 文件将如下所示：

/// <reference path="globals/bluebird/index.d.ts" />
/// <reference path="globals/mongoose/index.d.ts" />
type MongoosePromise<T> = bluebird.Promise<T>;