Pio*_*rek 2 c# asp.net angularjs angular
后端,ASP.net核心API:
[Produces("application/json")]
[Route("api/[controller]")]
public class StoriesController : Controller
{
public static List<Story> STORIES = new List<Story>
{
new Story
{
content = "Some really interesting story about dog",
timeOfAdding = new DateTime(2016, 8, 26),
numberOfViews = 11
},
new Story
{
content = "Even cooler story about clown",
timeOfAdding = new DateTime(2016, 9, 26),
numberOfViews = 11
},
new Story
{
content = "And some not cool story",
timeOfAdding = new DateTime(2016, 10, 26),
numberOfViews = 11
}
};
// POST api/values
[HttpPost]
public void Post([FromBody]string value)
{
Story story = new Story
{
content = value,
timeOfAdding = DateTime.Now,
numberOfViews = 0
};
STORIES.Add(story);
}
}
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TypeScript函数:
add(content: string): Observable<Story> {
let body = JSON.stringify({ "value": content });
//let body = { "value": content };
let headers = new Headers({ 'Content-Type': 'application/json' });
let options = new RequestOptions({ headers: headers});
return this.http.post(this.heroesUrl, body, options)
.map(this.extractData)
.catch(this.handleError);
}
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发送的参数(在Firefox控制台中看到):
value = null 在Visual Studio 2015调试器中
怎么了?我已经尝试了我在互联网上找到的所有东西:添加/删除标题,删除JSON.stringify,添加/删除[FromBody]属性.结果是每次都一样.
由于您将值作为JSON传递(如屏幕截图所示),您应该正确使用模型绑定并使用适当的类而不是字符串输入:
public class StoryAddRequest
{
public string Value { get; set; }
}
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然后,您可以在控制器中使用它:
// POST api/values
[HttpPost]
public void Post([FromBody] StoryAddRequest request)
{
if (request != null)
{
Story story = new Story
{
content = request.Value,
timeOfAdding = DateTime.Now,
numberOfViews = 0
};
STORIES.Add(story);
}
}
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从文档:
请求数据可以有多种格式,包括JSON,XML和许多其他格式.当您使用该
[FromBody]属性指示要将参数绑定到请求正文中的数据时,MVC使用一组已配置的格式化程序来根据其内容类型处理请求数据.默认情况下,MVC包含一个JsonInputFormatter用于处理JSON数据的类,但您可以添加其他格式化程序来处理XML和其他自定义格式.