bob*_*lie 5 php forms validation codeigniter
我有一张带桌子的表格.该表包括三个用户输入.数量,行项目和价格.在用户提交表单之前,我需要填写所有三个.该表允许添加行.
这是我的桌子.
<form id="add_quote_form" name="add_quote_form" class="form-horizontal">
<table style="width: 90%" id="myTable" class="centered-table table table-bordered">
<thead>
<tr>
<th>Item</th>
<th>Qty</th>
<th>Price</th>
<th>Action</th>
</tr>
</thead>
<tbody>
<tr>
<td style="width: 60%"><input type="text" name="detail[]"required></td>
<td style="width: 10%"><input type="number" name="qty[]" required></td>
<td style="width: 15%"><input type="number" name="price[]" required></td>
<td style="width: 12%"><div class="inline"><input type="button" id="addButton" class="btn btn-primary btn-xs" value="Add"/></div><div class="inline"><input type="button" id="deleteButton" class="btn btn-primary btn-xs" value="Delete"/></div>
</tr>
</tbody>
</table>
<input type="button" id="saveBtn" name="saveBtn" class="btn btn-primary" value="Create Order" onClick="this.disabled=true; add_quotation();return false;">
</form>
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向表中添加行的功能
$(function(){
$("#addButton").click(function(){
$(this).closest("tr").clone(true).appendTo("#myTable");
});
$("#deleteButton").click(function(){
// var x = document.getElementById("myTable").rows.length;
var x = $('#myTable tr').length;
if(x == 2){
} else {
$(this).closest("tr").remove();
}
});
});
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调用提交按钮的功能
function add_quotation() {
document.add_quote_form.saveBtn.value="Saving...";
var formArray = $('#add_quote_form').serialize();
jQuery.post('<?php echo base_url(); ?>index.php/quotes/add_work_order_validation/' , formArray, function(data)
{
//alert('here');
if (data.success)
{
//GetQuotesPage();
//location.reload(base_url+'quotes');
//window.location = base_url+'quotes';
document.add_quote_form.saveBtn.value="Save Order";
document.add_quote_form.saveBtn.disabled=false;
swal({
title: "Order Saved!",
// text: "You clicked the button!",
type: "success"
});
//alert("Quote Saved");
}
else
{
document.add_quote_form.saveBtn.value="Save Order";
document.add_quote_form.saveBtn.disabled=false;
for (var i in data.errors)
{
$('#'+i).css('border-color', 'red');
$('#'+i).validationEngine('showPrompt', data.errors[i], '', 'topRight', true);
}
for (var z in data.hidden)
{
$('#add_quote_form#' +data.hidden[z]).validationEngine('hide');
}
}
}, 'json');
return false;
}
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这是我的控制器
public function add_work_order_validation()
{
$this->form_validation->set_rules('quoteName', 'Quote Name', 'trim|required');
$this->form_validation->set_rules("dueDate", "Due Date", "trim|required");
$this->form_validation->set_rules('detail[]', 'Line Items','required|trim|callback_matchLineItems');
if ($this->form_validation->run() == FALSE)
{
$result['errors'] = array();
$result['hidden'] = array();
$result['success'] = false;
$fields = array('quoteName', "dueDate", "detail");
foreach ($fields as $field)
{
if (form_error($field))
{
$result['errors'][$field] = strip_tags(form_error($field));
}
else
{
$result['hidden'][] = $field;
}
}
}
else
{ //Post Form
}
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最后一部分是我的回调功能
function matchLineItems() {
$detailArray = $this->input->post("detail");
$qtyArrayPost = $this->input->post("qty");
$priceArray = $this->input->post("price");
$qtyNumberCount = count($qtyArrayPost);
$priceNumberCount = count($priceArray);
$detailNumberCount = count($detailArray);
if($qtyNumberCount != $priceNumberCount || $qtyNumberCount != $detailNumberCount || $detailNumberCount != $priceNumberCount) {
$this->form_validation->set_message('matchLineItems', 'No Fields Can Be Left Blank');
return FALSE;
} else {
return TRUE;
}
}
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我遇到的问题是当我将订单项字段留空时,表单未提交但未显示错误.如果我在行项目字段中输入数据但将数量和价格字段留空,则表单提交.我是否需要为表中的每个字段创建验证?如何显示错误?
Codeigniter 版本3.0.6
对于像这样的领域
<input type="text" class="form-control" id="firstname" name="firstname" placeholder="Guest's First Name">
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添加一个简单的标签,如下所示
<p class="firstname_error error"></p>
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然后使用jquery检查
var firstname = $('#firstname').val();
if(firstname == '' || firstname == null)
{
valid = false;
$(".firstname_error").html("* Firstname is required");
}
else
{
$(".firstname_error").html("");
}
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并使用条件添加主要部分
if(valid==true){
//your main jquery code
}
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另外,如果您使用 CI 方法进行表单验证,则必须指定位置,例如
<?php echo form_error('username'); ?>
<input type="text" name="username" value="<?php echo set_value('username'); ?>" size="50" />
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正如其教程中提到的https://www.codeigniter.com/userguide3/libraries/form_validation.html#showing-errors-individually
这里的测试细节有限,是您的代码的解决方法https://jsfiddle.net/kmvgty/napz948b/1/
刚刚为每个选项卡添加了一个 id,并且有类似的 js
$('#saveBtn').on('click', function() {
var detail = $('#detail').val();
var qty = $('#qty').val();
var price = $('#price').val();
if ((detail == '') || (detail == null)) {
valid = false;
$('#erropr').removeClass('hide');
$('#erropr').html('* Enter an item');
} else {
$('#erropr').html('');
}
// same way for other
});
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当然,您的情况会有所不同,但这只是一个建议,看看小提琴是否可以帮助您