使用sql server检查字谜

Question

ACT和CAT是字谜

我必须写一个函数,sql server它需要2个字符串并给出一个布尔输出,指示它们是否都是字谜.

这在sql server中没有意义,但是,它仅用于学习目的

Answer 1

SQL Server并不擅长此类事情,但在这里你是:

WITH Src AS
(
    SELECT * FROM (VALUES
    ('CAT', 'ACT'),
    ('CAR', 'RAC'),
    ('BUZ', 'BUS'),
    ('FUZZY', 'MUZZY'),
    ('PACK', 'PACKS'),
    ('AA', 'AA'),
    ('ABCDEFG', 'GFEDCBA')) T(W1, W2)
), Numbered AS
(
    SELECT *, ROW_NUMBER() OVER (ORDER BY (SELECT 1)) Num
    FROM Src
), Splitted AS
(
    SELECT Num, W1 Word1, W2 Word2, LEFT(W1, 1) L1, LEFT(W2, 1) L2, SUBSTRING(W1, 2, LEN(W1)) W1, SUBSTRING(W2, 2, LEN(W2)) W2
    FROM Numbered
    UNION ALL
    SELECT Num, Word1, Word2, LEFT(W1, 1) L1, LEFT(W2, 1) L2, SUBSTRING(W1, 2, LEN(W1)) W1, SUBSTRING(W2, 2, LEN(W2)) W2
    FROM Splitted
    WHERE LEN(W1)>0 AND LEN(W2)>0
), SplitOrdered AS
(
    SELECT *,
        ROW_NUMBER() OVER (PARTITION BY Num ORDER BY L1) LNum1,
        ROW_NUMBER() OVER (PARTITION BY Num ORDER BY L2) LNum2
    FROM Splitted
)
SELECT S1.Num, S1.Word1, S1.Word2, CASE WHEN COUNT(*)=LEN(S1.Word1) AND COUNT(*)=LEN(S1.Word2) THEN 1 ELSE 0 END Test
FROM SplitOrdered S1
JOIN SplitOrdered S2 ON S1.L1=S2.L2 AND S1.Num=S2.Num AND S1.LNum1=S2.LNum2
GROUP BY S1.Num, S1.Word1, S1.Word2

结果:

1   CAT     ACT     1
2   CAR     RAC     1
3   BUZ     BUS     0
4   FUZZY   MUZZY   0
5   PACK    PACKS   0
6   AA      AA      1
7   ABCDEFG GFEDCBA 1