如何在 JavaScript 中删除 JSON 字符串中的第一个和最后一个双引号？

Question

大家好，我想从 JSON 字符串的第一个和最后一个位置删除双引号，我需要将一个 JSON 对象放在另一个对象中，然后我将显示我的代码和我的要求。

var sysMsg = new Object();
    sysMsg.timestamp = "100";
    sysMsg.seq  = "5";
    sysMsg.serviceid = "21";
    sysMsg.srcip = "192.168.0.1";
    sysMsg.ver = "1.0";
var sysString= JSON.stringify(sysMsg);
window.alert(sysString);        

var systmMsg = new Object();
systmMsg.sys =  sysString;  
// JSON.stringify(hdrString);
var sysFinal= JSON.parse(systmMsg);
alert(sysFinal);
sysFinal = sysFinal.replace(/\\/g, "");
window.alert(sysFinal);                             

var hdrMsg = new Object();
hdrMsg.appcontext = "context";
hdrMsg.appname  = "appName";
hdrMsg.appid = "identifier";
hdrMsg.cmd = "command";
hdrMsg.timeout = "500";
hdrMsg.option = "optionCommand";
var hdrString= JSON.stringify(hdrMsg);
//window.alert(hdrString);  
var hdrFinal = new Object();
hdrFinal.hdr =  hdrString;                             
var hdrFinalMsg= JSON.stringify(hdrFinal);
hdrFinalMsg = hdrFinalMsg.replace(/\\/g, "");
window.alert(hdrFinalMsg);

var dataMsg = new Object();
dataMsg.CntrlID = "6";
dataMsg.Devinst  = "1";
dataMsg.btnstatus = "btnStatus";
dataMsg.DevID = "33";
dataMsg.value = "true";
dataMsg.status = "errorStatus";
var dataString = JSON.stringify(dataMsg);
//window.alert(dataString);

var dataFinal = new Object();
dataFinal.data =  dataString;                             
var dataFinalMsg= JSON.stringify(dataFinal);
dataFinalMsg = dataFinalMsg.replace(/\\/g, "");
window.alert(dataFinalMsg);

var appData = hdrFinalMsg.concat(dataFinalMsg);
var appFinal = new Object();
appFinal.app =  JSON.stringify(appData);
var appFinalMsg= JSON.stringify(appFinal);
appFinalMsg = appFinalMsg.replace(/\\/g, "");
window.alert(appFinalMsg);

var finalData = appFinalMsg.concat(sysFinal);
var finalMsg= JSON.stringify(finalData);
finalMsg = finalMsg.replace(/\\/g, "");
window.alert(finalMsg);

在这里，我得到的字符串如下

"{"app":""{"hdr":"{"appcontext":"context","appname":"appName","appid":"identifier","cmd":"command","timeout":"500","option":"optionCommand"}"}{"data":"{"CntrlID":"6","Devinst":"1","btnstatus":"btnStatus","DevID":"33","value":"true","status":"errorStatus"}"}""}{"sys":"{"timestamp":"100","seq":"5","serviceid":"21","srcip":"192.168.0.1","ver":"1.0"}"}"

但我想要如下输出

{"app":{"data":{"Cntrl.ID":"6","Dev.inst":"1","btn.status":"btnStatus","Dev.ID":"33","value":"true","status":"errorStatus"},"hdr":{"appcontext":"context","appname":"appName","appid":"identifier","cmd":"set","timeout":"500","option":"optionCommand"}},"sys":{"srcip":"192.168.0.1","ver":"1.0","serviceid":"21","seq":"5","timestamp":"100"}}

Answer 1

干得好

var yourString = "{JsonString}";
var result = yourString.substring(1, yourString.length-1);

或者你可以使用 .slice

var result = yourString.slice(1, -1);