无法以编程方式使UIButton工作 - iPhone

Question

这是我正在使用的代码:

-(void)viewDidLoad
{
    NSString *checkerPath = [[NSBundle mainBundle] pathForResource:@"black-yellow-checker" ofType:@"png"];
    UIImage *checkerImage = [[UIImage alloc] initWithContentsOfFile:checkerPath];
    checkerView = [[UIImageView alloc] initWithFrame:CGRectMake(0.0f, 230.0f, 320.0f, 280.0f)];
    [checkerView setImage:checkerImage];

    UIButton *backButton = [[UIButton buttonWithType:UIButtonTypeCustom] retain];
    backButton.frame = CGRectMake(45.0f, 175.0f, 230.0f, 50.0f);
    [backButton setBackgroundImage:[UIImage imageWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"yellowButton" ofType:@"png"]] forState:UIControlStateNormal];
    [backButton addTarget:self action:@selector(goBackHome:) forControlEvents:UIControlEventTouchDown];
    [backButton setTitle:@"Back" forState:UIControlStateNormal];
    backButton.titleLabel.font = [UIFont fontWithName:@"Marker Felt" size:30];
    backButton.titleLabel.textColor = [UIColor blackColor];
    [checkerView addSubview:backButton];
}

- (void)goBackHome:(id)sender
{
    NSLog(@"go back pressed");
}

不知道为什么这不起作用.按钮出现,但是当我按下按钮时没有任何反应.当我触摸它时,它甚至不会改变为"缩进"图像.没有.不能使用IB,必须以编程方式.有什么想法吗？

Answer 1

UIImageView userInteractionEnabled默认设置为NO.这可以防止任何子视图被触及.

您可以启用图像视图的用户交互

checkerView.userInteractionEnabled = YES;

或创建一个新的UIView包括checkerView和backButton.

UIView* newView = ...
...
[newView addSubview:checkerView];
[newView addSubview:backButton];