广播到凤凰城1.1.6的不同频道

Question

我正在尝试在我的应用中播放到不同的频道,但我无法让它工作.我也试着写一个测试,但我不确定如何.

从我可以收集的内容中,我成功地从notification_channel广播消息,但是在chat_channel中没有收到消息.

通知应发送到聊天.

notification_channel.ex

  def handle_in("new:group:recommendation", msg, socket) do
    payload = %{
        message: msg["message"],
        url: msg["url"],
        title: msg["title"],
        user_name: get_name_of_user(socket.assigns.user_grapqhl_id),
        user_grapqhl_id: socket.assigns.user_grapqhl_id
    }

    IO.puts "incomming"
    IO.inspect msg
    Enum.map(msg["groups"], fn(x) ->
        App.Endpoint.broadcast_from! self(), "chat:"<>x,
            "new:recommendation", payload
        end)
    {:reply, :ok, socket}

  end

chat_channel.ex

 def handle_in("new:recommendation", msg, socket) do
      IO.puts "i am a recommendation !"
      IO.inspect msg
      chat_msg = %{
         "creator_id" => msg["user_grapqhl_id"],
         "text" => msg["message"],
         "creator_name" => msg["user_name"]
      }

     broadcast! socket, "new:msg", create_chat_msg(chat_msg,socket)
     {:reply, :ok, socket}
  end

测试

  test "do we send a new:recommendation to chat ?", %{guardian_token: guardian_token} do
      nils_base_64 = Base.encode64("user:nils")

      {:ok, socket} = connect(UserSocket, %{})
      {:ok, _, socket1} = subscribe_and_join(socket, "notifications:"<>nils_base_64, %{"guardian_token" => guardian_token})
      {:ok, _, socket} = subscribe_and_join(socket1, "chat:Y2hhdDpjaGF0Mw==", %{"guardian_token" => guardian_token})

      payload = %{
          "message" => "look at this cool thing!",
          "url" => "link to stuff",
          "title" => "AWESOME EVENT",
          "groups" => ["Y2hhdDpjaGF0Mw==", "Y2hhdDpwdWJsaWM="]
      }

      reply = %{message: "look at this cool thing!", title: "AWESOME EVENT", url: "link to stuff", user_grapqhl_id: nils_base_64, user_name: "Nils Eriksson"}

      ref = push socket1, "new:group:recommendation", payload
      assert_reply ref, :ok
      assert_broadcast "new:recommendation", ^reply
  end

这个测试通过了,我可以通过改变reply 或评论广播来使它失败.我不能让它改变失败handle_in,以获得fail:please在chat_channel.如果我在这种情况下将改变发送ref = push socket1, "new:group:recommendation", payload 给ref = push socket, "new:group:recommendation", payload不支持,那就是它会抱怨的东西 .

这就是电线上的内容.

     Process mailbox:
   %Phoenix.Socket.Message{event: "init:msgs", payload: %{messages: []}, ref: nil, topic: "chat:Y2hhdDpjaGF0Mw=="}
   %Phoenix.Socket.Broadcast{event: "new:recommendation", payload: %{message: "look at this cool thing!", title: "AWESOME EVENTs", url: "link to stuff", user_grapqhl_id: "dXNlcjpuaWxz", user_name: "Nils Eriksson"}, topic: "chat:Y2hhdDpjaGF0Mw=="}
   %Phoenix.Socket.Message{event: "new:recommendation", payload: %{message: "look at this cool thing!", title: "AWESOME EVENTs", url: "link to stuff", user_grapqhl_id: "dXNlcjpuaWxz", user_name: "Nils Eriksson"}, ref: nil, topic: "chat:Y2hhdDpjaGF0Mw=="}

我使用通道身份验证,因为我使用的elm包不支持套接字级别的身份验证.所以这就是它的样子chat

  def join("chat:" <> chat_id, %{"guardian_token" => token}, socket) do
  IO.puts chat_id
  case sign_in(socket, token) do
     {:ok, authed_socket, _guardian_params} ->
         Process.flag(:trap_exit, true)
         send(self, {:after_join})
         [_type, node_chat_id] = Node.from_global_id(chat_id)
         {:ok, assign(authed_socket, :chat_id, node_chat_id)}
     {:error, reason} ->
         IO.puts "Can't join channel cuz: " <> reason
       # handle error TODO
   end

结束

Answer 1

既然你使用broadcast_from/4了你的Endpoint.你应该使用handle_info/2你的chat_channel:

alias Phoenix.Socket.Broadcast
  ...

def handle_info(%Broadcast{topic: _, event: ev, payload: payload}, socket) do
    IO.puts ev
    IO.inspect payload
    # do something with ev and payload( push or broadcast)
    {:noreply, socket}
  end

或者您可以从您的客户那里听取该事件:

chatChannel.on("new:recommendation", resp => {
   // doSomething with response
}

编辑:

让我们简要介绍一下如何channel和PubSub系统正常工作.

当您想要播放或推送带有有效载荷的事件时.首先,它将发送到PubSub系统,然后PubSub系统将其发送到所有订户进程(channel),其主题channel已在PubSub系统中注册.

当您用于Endpoint.broadcast_from/4从服务器广播事件时.PubSub系统将接收带有效负载的事件,并将该事件广播到已注册频道的主题.

该通道将触发handle_out回调并将消息推送到客户端.因此,在您的工作中,chat_channel您不需要handle_in"新建:推荐"活动.您的客户只需要听取该事件.

chatChannel.on("new:recommendation", resp => {
   // do something with response
}

让我改写你的测试:

setup do
    nils_base_64 = Base.encode64("user:nils")
    {:ok, socket} = connect(UserSocket, %{})
    {:ok, _, socket} = subscribe_and_join(socket, "notifications:"<>nils_base_64, %{"guardian_token" => guardian_token})
    {:ok, socket: socket}
  end


test "do we send a new:recommendation to chat ?", %{socket: socket} do
      MyApp.Endpoint.subscribe("chat:Y2hhdDpjaGF0Mw==")

      payload = %{
          "message" => "look at this cool thing!",
          "url" => "link to stuff",
          "title" => "AWESOME EVENT",
          "groups" => ["Y2hhdDpjaGF0Mw==", "Y2hhdDpwdWJsaWM="]
      }



      reply = %Phoenix.Socket.Broadcast{message: "look at this cool thing!",
              title: "AWESOME EVENT",
              url: "link to stuff",
              user_grapqhl_id: nils_base_64,
              user_name: "Nils Eriksson"}

      ref = push socket, "new:group:recommendation", payload
      assert_reply ref, :ok
      assert_receive ^reply
  end

通过subscribe您想要收听的主题,您可以确保收到您的频道的消息assert_receive.这是测试broadcast不同频道的方法.

试一试告诉我.测试将通过.