fir*_*tte 2 python beautifulsoup web-scraping
我想获得一个列表,其中包含HTML文档的所有不同标记名称(标记名称字符串列表,不重复).我尝试将空条目放入soup.findall(),但这给了我整个文档.
有办法吗？
使用soup.findall()您可以获得可以迭代的每个元素的列表.因此,您可以执行以下操作:
from bs4 import BeautifulSoup
html_doc = """
<html><head><title>The Dormouse's story</title></head>
<body>
<p class="title"><b>The Dormouse's story</b></p>
<p class="story">Once upon a time there were three little sisters; and their names were
<a href="http://example.com/elsie" class="sister" id="link1">Elsie</a>,
<a href="http://example.com/lacie" class="sister" id="link2">Lacie</a> and
<a href="http://example.com/tillie" class="sister" id="link3">Tillie</a>;
and they lived at the bottom of a well.</p>
<p class="story">...</p>
""" # an html sample
soup = BeautifulSoup(html_doc, 'html.parser')
document = soup.html.find_all()
el = ['html',] # we already include the html tag
for n in document:
if n.name not in el:
el.append(n.name)
print(el)
代码段的输出将是:
>>> ['head', 'title', 'body', 'p', 'b', 'a']
作为@PM 2Ring指了指摆在那里,如果你不关心它的元素被添加(这正如他所说的,我不认为它是如此)的顺序,那么你可以使用套.在Python 3.x中,您不必导入它,但如果您使用旧版本,则可能需要检查它是否受支持.
from bs4 import BeautifulSoup
...
el = {x.name for x in document} # use a set comprehension to generate it easily
el.add("html") # only if you need to