Python,如何将.wav文件拆分为多个.wav文件

Question

我有几分钟的.wav文件,我想分成不同的10秒.wav文件.

到目前为止这是我的python代码:

import wave
import math

def main(filename, time):
    read = wave.open(filename, 'r')

#get sample rate
    frameRate = read.getframerate()

#get number of frames
    numFrames = read.getnframes()

#get duration
    duration = numFrames/frameRate

#get all frames as a string of bytes
    frames = read.readframes(numFrames)

#get 1 frame as a string of bytes
    oneFrame = read.readframes(1)

#framerate*time == numframesneeded
    numFramesNeeded=frameRate*time

#numFramesNeeded*oneFrame=numBytes
    numBytes = numFramesNeeded*oneFrame

#splice frames to get a list strings each representing a 'time' length
#wav file
    x=0
    wavList=[]
    while x+time<=duration:
        curFrame= frames[x:x+time]
        x=x+time
        wavList.append(curFrame)

打印"wavList"产生:

['\ x00\x00\x00\x00\xff\xff\x00\x00\x00\x00','\ x00\x00\x00\x00\x00\x00\x00\x00\x00\x00','\ x00\x00\x00\x00\x00\x00\x00\x00\x00\x00','\ x00\x00\x00\x00\x00\x00\x00\x00\x00\x00','\ x00\x00\x00\X00\X00\X00\X00\X00\X00\X00' ]

我知道这是一个框架列表.如何为此列表中的每个元素创建一个wav文件(第一个.wav文件将是'\ x00\x00\x00\x00\xff\xff\x00\x00\x00\x00')？Python的wave模块不清楚使用框架来创建.wav文件.

编辑:这是如何在python中将音频文件(wav格式)拼接成1秒拼接的重复问题？ 但是,如果某人有一个不需要的答案,pydub我非常希望看到它.

Answer 1

这是一个python代码片段,我根据需要使用它来分割文件.
我使用https://github.com/jiaaro/pydub上的pydub库.您可以修改代码段以满足您的要求.

from pydub import AudioSegment
t1 = t1 * 1000 #Works in milliseconds
t2 = t2 * 1000
newAudio = AudioSegment.from_wav("oldSong.wav")
newAudio = newAudio[t1:t2]
newAudio.export('newSong.wav', format="wav") #Exports to a wav file in the current path.

Answer 2

我写了一个类来简化整个过程。虽然它是用于wav文件的。

这里是：

from pydub import AudioSegment
import math

class SplitWavAudioMubin():
    def __init__(self, folder, filename):
        self.folder = folder
        self.filename = filename
        self.filepath = folder + '\\' + filename
        
        self.audio = AudioSegment.from_wav(self.filepath)
    
    def get_duration(self):
        return self.audio.duration_seconds
    
    def single_split(self, from_min, to_min, split_filename):
        t1 = from_min * 60 * 1000
        t2 = to_min * 60 * 1000
        split_audio = self.audio[t1:t2]
        split_audio.export(self.folder + '\\' + split_filename, format="wav")
        
    def multiple_split(self, min_per_split):
        total_mins = math.ceil(self.get_duration() / 60)
        for i in range(0, total_mins, min_per_split):
            split_fn = str(i) + '_' + self.filename
            self.single_split(i, i+min_per_split, split_fn)
            print(str(i) + ' Done')
            if i == total_mins - min_per_split:
                print('All splited successfully')

用法

folder = 'F:\\My Audios\\Khaled'
file = 'Khaled Speech.wav'
split_wav = SplitWavAudioMubin(folder, file)
split_wav.multiple_split(min_per_split=1)

就是这样！它会将single wav文件拆分为multiple wav具有1 minute持续时间的文件。最后一个分割音频的持续时间可能少于 1 分钟；)

注意：如果您使用的是 Mac/Linux，请更改\\为/

Answer 3

对于那些专门为该模块寻求答案的人wave。

import wave

# times between which to extract the wave from
start = 5.2 # seconds
end = 78.3 # seconds

# file to extract the snippet from
with wave.open('my_in_file.wav', "rb") as infile:
    # get file data
    nchannels = infile.getnchannels()
    sampwidth = infile.getsampwidth()
    framerate = infile.getframerate()
    # set position in wave to start of segment
    infile.setpos(int(start * framerate))
    # extract data
    data = infile.readframes(int((end - start) * framerate))

# write the extracted data to a new file
with wave.open('my_out_file.wav', 'w') as outfile:
    outfile.setnchannels(nchannels)
    outfile.setsampwidth(sampwidth)
    outfile.setframerate(framerate)
    outfile.setnframes(int(len(data) / sampwidth))
    outfile.writeframes(data)