Kev*_*rne 4 java jax-rs java-ee resteasy java-ee-7
我只需要将查询参数附加到传出请求上.(Java EE 7.0,JAX-RS 2.0)
具体来说,我目前使用RESTeasy Client ver 3.0.14,所以我使用花哨的接口代理系统进行调用.我试图产生这样的东西:
myapplication/api/path?timestamp=000
有:
@Provider
public class MyRequestFilter implements ClientRequestFilter {
@Context
private HttpServletRequest servletRequest;
public void filter(ClientRequestContext requestContext) throws IOException {
servletRequest.getParameterMap().put("timestamp", new String[]{
String.valueOf(new Date().getTime())
});
}
}
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我确定我也在注册它client.register(MyRequestFilter.class).随意问的问题.谢谢!
归功于@peeskillet -
从requestContext这样重建URI :
requestContext.setUri(UriBuilder.fromUri(requestContext.getUri()).queryParam("key", value).build());
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您现在可以看到新的查询参数
requestContext.getUri().toString();
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再次,验证您在制作REST客户端时注册它
client.register(MyRequestFilter.class);
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